Solve by Method of Branch Current by using figure 1.|R3=15R1=5R5=25R6=30Loop1Loop 2Loop 3R4=20 CWCwACWR2=10390 V60 V30 VFigure 1

Answered: Solve by Method of Branch Current by…

Solve by Method of Branch Current by using figure 1. R1=5 R3=15 R5=25 R6=30 Loop1 cw R2=103 Loop 2 Loop 3 R4=20 CW ACW 90 V 60 V 30 V

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Solve by Method of Branch Current by using figure 1.
|
R3=15
R1=5
R5=25
R6=30
Loop1
Loop 2
Loop 3
R4=20 CW
Cw
ACW
R2=103
90 V
60 V
30 V
Figure 1

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