Some amount of heat energy is removed from a 6cm X 20cm X 34cm block of ice to cool from 0°C to -24°C. (Hint: to find mass, use the relation between, density, mass and volume) (b*1)+(c*2) = 5marks) ((a*2)+ Calculate the following: a) The mas of ice cube in grams (density of ice = 920 kg/m³). b) The temperature difference in kelvin b) The energy removed from ice in calories . (specific heat of ice = 2093 J/kg°C)

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Some amount of heat energy is removed from a
6cm X 20cm X 34cm block of ice to cool from
0°C to -24°C. (Hint: to find mass, use the relation
between, density, mass and volume) (a*2)+
(b*1)+(c*2) = 5marks)
Calculate the following:
a) The mas of ice cube in grams
(density of ice = 920 kg/m³).
b) The temperature difference in kelvin
b) The energy removed from ice in calories
. (specific heat of ice = 2093 J/kg°C)
Transcribed Image Text:Some amount of heat energy is removed from a 6cm X 20cm X 34cm block of ice to cool from 0°C to -24°C. (Hint: to find mass, use the relation between, density, mass and volume) (a*2)+ (b*1)+(c*2) = 5marks) Calculate the following: a) The mas of ice cube in grams (density of ice = 920 kg/m³). b) The temperature difference in kelvin b) The energy removed from ice in calories . (specific heat of ice = 2093 J/kg°C)
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