Steam at P1 = 1600 psi and T1 = 1000°F enters a turbine operating at steady state at a mass flow rate of mi= 2 x 10° lb/hr with 20% of the entering mass flow extracted at P2 = 160 psi and T2= 450°F. The rest of the steam exits as a two-phase liquid- vapor mixture at P3 = 1 psi, with a quality of x3 = 80%. Determine the work output of the turbine per unit mass entering the turbine in Btu/lb and the power output of the turbine in Btu/hr.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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State what to find , assumption, and a simple sketch of the turbine. and then solve for the work output. 

Chapter 4 Conservation of Energy
1600 psi and Tı = 1000°F enters a turbine operating at steady state at
2 x 10° Ib/hr with 20% of the entering mass flow extracted
160 psi and T2 = 450°F. The rest of the steam exits as a two-phase liquid-
vapor mixture at P3 = 1 psi, with a quality of x3 = 80%. Determine the work output
of the turbine per unit mass entering the turbine in Btu/lb and the power output of
Steam at P1
a mass flow rate of mi=
at P2
the turbine in Btu/hr.
Given: P1 = 1600 psi P2 = 160 psi
P3 = 1 psi
mi = 2 x 106 lb/hr
%D
T1 = 1000°F
T2 = 450°F
X3 = 80%
m2/mı = 0.20
Find:
Turbine Sketch:
Property Data:
hi = 1487.1 Btu/lb
h2 = 1246.1 Btu/lb
Assume:
Һз [Рз, хз]
hr3 = 69.74 Btu/lb
hg3 = 1105.8 Btu/lb
h3
Transcribed Image Text:Chapter 4 Conservation of Energy 1600 psi and Tı = 1000°F enters a turbine operating at steady state at 2 x 10° Ib/hr with 20% of the entering mass flow extracted 160 psi and T2 = 450°F. The rest of the steam exits as a two-phase liquid- vapor mixture at P3 = 1 psi, with a quality of x3 = 80%. Determine the work output of the turbine per unit mass entering the turbine in Btu/lb and the power output of Steam at P1 a mass flow rate of mi= at P2 the turbine in Btu/hr. Given: P1 = 1600 psi P2 = 160 psi P3 = 1 psi mi = 2 x 106 lb/hr %D T1 = 1000°F T2 = 450°F X3 = 80% m2/mı = 0.20 Find: Turbine Sketch: Property Data: hi = 1487.1 Btu/lb h2 = 1246.1 Btu/lb Assume: Һз [Рз, хз] hr3 = 69.74 Btu/lb hg3 = 1105.8 Btu/lb h3
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