Stoichiometry Unit TestN2 (g) + 3H2 (g)2NH3 (g)(S) Indicate how to calculate the mass of ammonia (NH3) that would be produced from the reaction of 2.56 x 1023 molecules of nitrogen gaswith excess hydrogen gas?2.56 1023 molec N2The Periodic Table of the Elements18TRIADS> Mercury80Element name.Average relative massesare 2001 values, roundedto two decimal places.HyogenAtomic #He4.0013141516171.0121→Hg2.All average masses are tobe treated as measuredquantities, and subject tosignificant figure rules. Donot round them furtherwhen performingcalculations.Symbol -Soap10CabonLinNe4.Be200.59 < Avg. Mass19.004.020.18LI10.812012.012514.013.016.003.56.941.09.011.5Electronegativity1.9Agan18ONemtonPhosan15161714SI28.091813Sodum11Magneum12Al26.98CIAr39.9530.972132.072.535.453.0Na22.990.9Mg24.3112101112153.Dosee35AcwrcSeehOielNelCopper333436Cu3230Zn65.391.631Ga09.7216TourumVanadumChramu2829KrScandum27Pulaum19Br79.9028CatiumSe78.962526As74.92202021222324GeCr52.001.6Mn54.941.5Fe55.8518Co58.9318NI58.691.8Cu63.551.983.803.0TICa40.08.8Sc44.9613V50.941.672.61182439.100.847.881.5Autonary51Sb121.76Takm1.05354Co4850Sn118.7152Noadas45Paled46Pd49Magholarm42Testram43Tc47Xe131.2944TeRubidum37In114.82394041Cd38SrAg107 87MoRuRh127.60126 90Y.88.91Zr91.22Nb92.91112.41Rb95.94(98)101.07102.91106 4285.4787.62

Given, No of molecules of nitrogen gas = 2.56 × 1023 We know, According to avagadro number no of…

Stoichiometry Unit Test N2 (g) + 3H2 (g) 2NH3 (g) (S) Indicate how to calculate the mass of ammonia (NH3) that would be produced from the reaction of 2.56 x 1023 molecules of nitrogen gas with excess hydrogen gas? 2.56 1023 molec N2 The Periodic Table of the Elements

Stoichiometry Unit Test N2 (g) + 3H2 (g) 2NH3 (g) (S) Indicate how to calculate the mass of ammonia (NH3) that would be produced from the reaction of 2.56 x 1023 molecules of nitrogen gas with excess hydrogen gas? 2.56 1023 molec N2 The Periodic Table of the Elements

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter3: Molecules, Moles, And Chemical Equations

Section: Chapter Questions

Problem 3.123PAE: 3.123 Most periodic tables provide molar masses with four or five significant figures for the...

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Question

Stoichiometry Unit Test
N2 (g) + 3H2 (g)
2NH3 (g)
(S) Indicate how to calculate the mass of ammonia (NH3) that would be produced from the reaction of 2.56 x 1023 molecules of nitrogen gas
with excess hydrogen gas?
2.56 1023 molec N2
The Periodic Table of the Elements
18
TRIADS
> Mercury
80
Element name.
Average relative masses
are 2001 values, rounded
to two decimal places.
Hyogen
Atomic #
He
4.00
13
14
15
16
17
1.01
21
→Hg
2.
All average masses are to
be treated as measured
quantities, and subject to
significant figure rules. Do
not round them further
when performing
calculations.
Symbol -
Soap
10
Cabon
Lin
Ne
4.
Be
200.59 < Avg. Mass
19.00
4.0
20.18
LI
10.81
20
12.01
25
14.01
3.0
16.00
3.5
6.94
1.0
9.01
1.5
Electronegativity
1.9
Agan
18
ONemton
Phosan
15
16
17
14
SI
28.09
18
13
Sodum
11
Magneum
12
Al
26.98
CI
Ar
39.95
30.97
21
32.07
2.5
35.45
3.0
Na
22.99
0.9
Mg
24.31
12
10
11
12
15
3.
Dosee
35
Acwrc
Seeh
Oiel
Nel
Copper
33
34
36
Cu
32
30
Zn
65.39
1.6
31
Ga
09.72
16
Tourum
Vanadum
Chramu
28
29
Kr
Scandum
27
Pulaum
19
Br
79.90
28
Catium
Se
78.96
25
26
As
74.92
20
20
21
22
23
24
Ge
Cr
52.00
1.6
Mn
54.94
1.5
Fe
55.85
18
Co
58.93
18
NI
58.69
1.8
Cu
63.55
1.9
83.80
3.0
TI
Ca
40.08
.8
Sc
44.96
13
V
50.94
1.6
72.61
18
24
39.10
0.8
47.88
1.5
Autonary
51
Sb
121.76
Takm
1.0
53
54
Co
48
50
Sn
118.71
52
Noadas
45
Paled
46
Pd
49
Magholarm
42
Testram
43
Tc
47
Xe
131.29
44
Te
Rubidum
37
In
114.82
39
40
41
Cd
38
Sr
Ag
107 87
Mo
Ru
Rh
127.60
126 90
Y.
88.91
Zr
91.22
Nb
92.91
112.41
Rb
95.94
(98)
101.07
102.91
106 42
85.47
87.62

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