struct nodeType { int infoData; nodeType * next; }; nodeType *first; … and containing the values(see image) Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list.
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… and containing the values(see image)
- Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list. Ensure the code performs all memory ‘cleanup’ functions.
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- struct node{ int a; struct node * nextptr; }; Write two functions. One for inserting new values to a link list that uses the given node structure. void insert(struct node **head, int value); Second function is called to count the number of even numbers in the link list. It returns an integer that represents the number of even numbers. int countEvenNumbers(struct node *head); Write a C program that reads a number of integers from the user and insert those integers into a link list (use insert function). Later pass the head pointer of this link list to a function called countEvenNumbers. This function counts and returns the number of even numbers in the list. The returned value will be printed on the screen. Note 1: Do not modify the function prototypes. Sample Input1: Sample Output1: 45 23 44 12 37 98 33 35 -1 3 Sample Input2: Sample Output2: 11 33 44 21 22 99 123 122 124 77 -1 4Topic: Singly Linked ListImplement the following functions in C++ program. Read the question carefully. (See attached photo for reference) void isEmpty() This method will return true if the linked list is empty, otherwise return false. void clear() This method will empty your linked list. Effectively, this should and already has been called in your destructor (i.e., the ~LinkedList() method) so that it will deallocate the nodes created first before deallocating the linked list itself.Create two linked lists and then make a concatList(NODE **list1, NODE **list2) function that concatenates the two lists. The concatenated list must be a linked list. Fill in the "Write code here" sections appropriately.
- 1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…
- java Please provide Comment and test cases Create a Linked List data structure by writing your own Linked List class which contains a node class. The node class will house the data (integer in this case) and a pointer to the next node element. Populate your linked list with the following integers and print it . 50, 11, 33, 21, 40, 71 No you do not need to print the commas ;) Delete N-th node from the end of the linked list and print the linked list after deletion. Here N = 2 Below is the expected output after deleting the second last element. 50, 11, 33, 21, 71 ATTN : Note : Here we do not know the length of the list. Complete the above deletion operation without calculating the length of the list. Your solution should only make a single pass through the linked list, adhering to O(n) time complexity overall and O(1) space complexity. Hint : Maintain two pointers : a ’Fast’ Pointer and a ’Slow’ pointer. Initialize both pointers to a dummy node which points to the head of the list.…using namespace std; class SinglyLinkedListNode { // INSERT YOUR CODE HERE }; class SinglyLinkedList { public: SinglyLinkedListNode *head; SinglyLinkedListNode *tail; SinglyLinkedList() { this->head = nullptr; this->tail = nullptr; } voidinsert_node(intnode_data) { // INSERT YOUR CODE HERE } }; void free_singly_linked_list(SinglyLinkedListNode* node) { // INSERT YOUR CODE HERE } // Complete the has_cycle function below. /* * For your reference: * * SinglyLinkedListNode { * int data; * SinglyLinkedListNode* next; * }; * */ bool has_cycle(SinglyLinkedListNode* head) { SinglyLinkedListNode* temp = head; bool isCycle = false; while (temp != nullptr) { // INSERT YOUR CODE HERE } } int main() { // INSERT YOUR CODE HERE TO TEST YOUR CODE return0; }class Node: def __init__(self, e, n): self.element = e self.next = n class LinkedList: def __init__(self, a): # Design the constructor based on data type of a. If 'a' is built in python list then # Creates a linked list using the values from the given array. head will refer # to the Node that contains the element from a[0] # Else Sets the value of head. head will refer # to the given LinkedList # Hint: Use the type() function to determine the data type of a self.head = None # To Do # Count the number of nodes in the list def countNode(self): # To Do # Print elements in the list def printList(self): # To Do # returns the reference of the Node at the given index. For invalid index return None. def nodeAt(self, idx): # To Do
- // FILL IN THE BLANKS (LINKED-LISTS CODE) (C++)#include<iostream>using namespace std; struct ________ {int data ;struct node *next; }; node *head = ________;node *createNode() { // allocate a memorynode __________;temp = new node ;return _______ ;} void insertNode(){node *temp, *traverse;int n;cout<< "Enter -1 to end "<<endl;cout<< "Enter the values to be added in list"<<endl;cin>>n; while(n!=-1){temp = createNode(); // allocate memorytemp->data = ________;temp->next = ________;if ( ___________ == NULL){head = _________;} else {traverse = ( );while (traverse->next != ________{traverse = traverse-> ___________;} traverse->next= temp;} cout<<"Enter the value to be added in the list"<<endl;cin>>n; }} void printlist(){node *traverse = head; // if head == NULLwhile (traverse != NULL) { cout<<traverse->data<<" ";traverse = traverse->next;}} int main(){int option; do{cout<<"\n =============== MAIN…#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;}; bool DelOddCopEven(Node* headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif // definition of DelOddCopEven of Assignment 5 Part 1//Algorithm should: /*NOT destroy any of the originally even-valued node. This means that the originally even-valued nodes should be retained as part of the resulting list. Destroy…Don't copy from other websties a) Write a function to get the value of the Nthnode in a Linked List. [Note: The first (N=1) item in the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return False if the list has fewer than N elements. The Linked List structure supports the following function. def getHead(self): return self.head # it points to a Node structure The Node structure supports the following functions. def getData(self): return self.data # it returns the value stored in the Node def getNext(self): return self.next # it points to the next Node b) Write a function that counts the number of times a given integer occurs in a Linked List. Assume similar structures as defined in 1.