Suppose a 250. mL flask is filled with 0.80 mol of O, and 0.30 mol of SO,. This reaction becomes possible: 2SO, (g) + 0, (g) → 2S0,(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,, You can leave out the M symbol for molarity. so2 02 so, initial change equilibrium

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Chapter18: Chemical Equilibrium
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Suppose a 250. mL flask is filled with 0.80 mol of O2 and 0.30 mol of SO3. This reaction becomes possible: 2SO2(g) + O2(g) ~ 2SO3(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use r to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity.
Suppose a 250. mL flask is filled with 0.80 mol of O, and 0.30 mol of SO,. This reaction becomes possible:
2S0, (g) + O, (g) → 2so, (2)
Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of
each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has
come to equilibrium.
Use x to stand for the unknown change in the molarity of O,, You can leave out the M symbol for molarity.
so2
02
so,
initial
change
equilibrium
Transcribed Image Text:Suppose a 250. mL flask is filled with 0.80 mol of O, and 0.30 mol of SO,. This reaction becomes possible: 2S0, (g) + O, (g) → 2so, (2) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,, You can leave out the M symbol for molarity. so2 02 so, initial change equilibrium
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