Suppose a 500. mL flask is filled with 0.80 mol of NO and 1.8 mol of NO,. The following reaction becomes possible: NO, (g) + NO(g) - 2NO, (g) The equilibrium constant K for this reaction is 4.37 at the temperature of the flask. Calculate the equilibrium molarity of N0,. Round your answer to two decimal places. OM

Chemistry: Matter and Change
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Chapter17: Chemical Equilibrium
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Suppose a 500. mL flask is filled with 0.80 mol of NO and 1.8 mol of NO2. The following reaction becomes possible: NO3(g) + NO(g) - 2NO2(g) The equilibrium constant K for this reaction is 4.37 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 0.80 mol of NO and 1.8 mol of NO,. The following reaction becomes
possible:
NO, (g) + NO(g) → 2NO, (g)
The equilibrium constant K for this reaction is 4.37 at the temperature of the flask.
Calculate the equilibrium molarity of N0,. Round your answer to two decimal places.
?
Transcribed Image Text:Suppose a 500. mL flask is filled with 0.80 mol of NO and 1.8 mol of NO,. The following reaction becomes possible: NO, (g) + NO(g) → 2NO, (g) The equilibrium constant K for this reaction is 4.37 at the temperature of the flask. Calculate the equilibrium molarity of N0,. Round your answer to two decimal places. ?
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