Suppose, alist is a 2-dimensional list that is defined as follows. alist = [ [1], [2,3], [5,6,7] ] Which is the best option to access the last element of the last element of this list (i.e., 7)?
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Q4
Suppose, alist is a 2-dimensional list that is defined as follows.
alist = [ [1], [2,3], [5,6,7] ]
Which is the best option to access the last element of the last element of this list (i.e., 7)?
Question 4 options:
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alist[ len(alist) - 1 ][len(alist[len(alist) - 1]) - 1] |
|
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alist[ len(alist) - 1 ][len(alist[len(alist) - 1])] |
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alist[3][3] |
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alist[ len(alist) - 1 ][1] |
Step by step
Solved in 4 steps with 1 images
- Think about the following example: A computer program builds and modifies a linked list like follows:Normally, the program would keep tabs on two unique nodes, which are as follows: An explanation of how to use the null reference in the linked list's node in two common circumstancesAssume a linked list contains following integers: 4, 2, 6, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a; curNode=curNode->getNext(); head->setNext(curNode); head=head->getNext(); a=head->getItem(); A.2 B.4 C.6 D.15Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; curNode=curNode->getNext(); curNode=curNode->getNext(); int a=curNode->getItem()<<endl; Group of answer choices A.4 B.2 C.5 D.6
- Add a proper function to the following linked list that will copy all elements with value above average into another list , then apply it to the list created in main function and print your resultant list. Example: l.copy(l2); will copy all elements with value greater than average into l2 #include <iostream> using namespace std; struct node { int data; node *next,*prev; node(int d,node *p=0,node *n=0) { data=d; prev=p; next=n; } }; class list { node *head; public: list(); void print(); void add_end(int el); }; list::list() { head=0; } void list::add_end(int el) { if(head==0) head=new node(el); else { node *t=head; for(;t->next!=0;t=t->next); t->next=new node(el,t); } } void list::print() { for(node *t=head;t!=0;t=t->next) cout<<t->data<<" "; cout<<endl; } void main() { list l; l.add_end(7); l.add_end(3); l.add_end(9);…Consider the following implementation of the node and doubly linked-list: Extend the class doubly_linked_list by adding the following methods: *Largest method .This method should return the largest element in a doubly linked-list. *Delete method. This method should delete the first occurrence of an element (value) from a doubly linked-list. USE C++ PLEASE THE CODE : template <class type> class node{public:type info;node<type> * next;// nextnode<type> * prev;//back }; template <class type>class doubly_linked_list {//data membersprivate:node<type> *head, *tail;int length;public:doubly_linked_list(){head = tail = NULL;length = 0;}bool isEmpty(){ // return (head==NULL);if (head == NULL)return true;elsereturn false;} void Append(type e){node<type> *newnode = new node<type>;newnode->info = e;if (isEmpty()){newnode->next = NULL;newnode->prev = NULL;head = newnode;tail = newnode;}else{tail->next = newnode;newnode->prev =…Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; curNode->setNext(NULL); while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.5 B.2 C.43 D.38
- Computer Science Describe a situation where you may wish to create a link list of ITERATORS. Is it possible to create a link list of various types of iterators? For example a list with list iterators, map iterators, and set iterators?Using a doubly linked list class and node class, implement the following methods: Node* lastNode(void); void pushBack(string argData); void popBack(void); void pushFront(string argData); void print(void); void printReverse(void); void insertAfter(Node* argPtr); void deallocateAll(void); Node* searchFor(string argData); int size(void); Hard code a linked list (no UI) in the main to demonstrate your functions. Print forward and backward to show that the links are well-formed.Please explai The list ADT interface and its implementation remove the need for the original list interface and its two implementing classes (ElementNode & EmptyNode). Group of answer choices A. True B. False C. No answer text provided. D. No answer text provided. Q#2, What is the type of the argument to a sort operation on a list? Group of answer choices A. Function B. Predicate C. Comparator D. BiFunction
- Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); if(curNode!=NULL) curNode=curNode->getNext(); } A.32 B.43 C.19 D.18Using java, write an easier version of a linked list with only a couple of the normal linked list functions and the ability to generate and utilize a list of ints. The data type of the connection to the following node can be just Node, and the data element can be just an int. You will need a reference like (Java) or either a reference to the first node, as well as one to the last node. (Answer the following questions) 1) Create a method or function that accepts an integer, constructs a node with that integer as its data value, and then includes the node to the end of the list. If the new node is the first one, this function will also need to update the reference to the first node. This function will need to update the reference to the final node. Consider how to insert the new node following the previous last node, and keep in mind that the next reference for the list's last node should be null. 2) Create a different method or function that iteratively explores the list, printing…Assume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode; curNode=new Node<int>(10,head); head=curNode; int a; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.49 B.39 C.7 D.15