Can anyone help me with this question I need to know num 1, 2 and the symbol for each. Thank you Remaining Time: 41 minutes, 34 seconds.v Question Completion Status:QUESTION 1Suppose num1 and num2 are int variables and symbol is a char variable.Consider the following input:47 18 * 28 $Given this statementcin >> num1 >> symbol >> num2%;BWhat are the values ofnum1 47num2 8symbol 1Starting over with the same input above evaluate these statementscin >> num1:cin.get(symbol);cin >> num2,What are the values ofnum1 47num2 18symbolUse two single quotes separated by a space to represent a space in the answersClick Save and Submit to save and subruit. Click Save ALAnswers to save all answers.a

For the first half We have the following output from the given requirements num1 is 47 num2 is 8…

Suppose num1 and num2 are int variables and symbol is a char variable. Consider the following input 47 18 * 28 $ Given this statement cin >> num1 >> symbol >> num2%3; What are the values of num1 47 num2 8 symbol 1 Starting over with the same input above evaluate these statements cin >> num 13; cin.get(symbol); cin >> num2; What are the values of num1 47 num2 18 symbol Use two single quotes separated by a space to represent a space in the answers

Suppose num1 and num2 are int variables and symbol is a char variable. Consider the following input 47 18 * 28 $ Given this statement cin >> num1 >> symbol >> num2%3; What are the values of num1 47 num2 8 symbol 1 Starting over with the same input above evaluate these statements cin >> num 13; cin.get(symbol); cin >> num2; What are the values of num1 47 num2 18 symbol Use two single quotes separated by a space to represent a space in the answers

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Assume that a box of apples cost 8 dollars and a box of grapes cost 6 dollars. Given variables numBoxApples and numBoxGrapes that are read from input, compute the total cost and assign combinedCost with the result. Ex: If the input is 7 10, then the output is: Cost: 116 include <iostream> using namespace std; int main() { int applePrice = 8; int grapePrice = 6; int numBoxApples; int numBoxGrapes; int combinedCost; cin >> numBoxApples; cin >> numBoxGrapes; /* Your code goes here */ cout << "Cost: " << combinedCost << endl; return 0; }
Each function should accept two integer parameters indicating the minimum and maximum X value to be plotted. The functions should have no return values. Create class-level constants for things we might wish to change later, e.g., a char called PLOT_CHAR that holds an “x” (per samples below), another char called FILL_CHAR that holds an unobtrusive character like ASCII 183, generated with a cast, e.g., (char)183. JAVA PLEASE THOSE ARE NOT PERIODS OR DOTS. USE (System.out.print((Char)183); for (.) Please DON'T USE Loops(while);, if, Arrays, lists, or other data structures, objects, libraries, or methods. Sideways Ploty = 20sin(.5x)+20 where -11<=x<=11 ··································x ·······································x ·······································x ···································x ···························x ·················x········x·xx···x··········x····················x ·····························x ····································x…
5.A)For the code segment below, what should be the values for q will result in kiwi being included in the output? switch(q) { case 1: cout << "apple"; break; case 2: cout << "orange"; break; case 3: cout << "banana"; break; case 4: cout << "pear"; case 5: cout << "grapes"; default: cout << "kiwi"; } B)Evaluate the following segment of a program. Show the procedure to reach your answer. int a = 3, b = 5, c = 2, d = 4; find: !(a / b > 0) && (22 > b % c + d) || !(a * d >= b – d / c) C) Write equivalent expressions for each of the following by using De Morgan’s Law. !(c == ‘r’ || (( y > 2) && !found ))
CHALLENGE ACTIVITY 6.7.3: Function with loop: Shampoo. Write a function print_shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.". Sample output with input: 2 1 : Lather and rinse. 2 : Lather and rinse. Done. Hint: Define and use a loop variable. Use Python, please.
Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word):if len(word) < 1:return False return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s(): assert(ends_with_s("cats")) # option 1 assert(ends_with_s("") is False) # option 2 assert(ends_with_s("apple") is False) # option 3 assert(ends_with_s("S")) # option 4 Rewrite ends_with_s so that the test passes
Use C++: Develop a Tic Tac Toe game that will match a player against the computer. Do’s: Use a typical 3 x 3 board. The horizontal axis should be labeled A, B, C. The vertical axis should be labeled 1, 2, 3. For Example the picture attatched. Use User-Defined Functions. Use Branching. Use Loops. Use String functions. Randomly determine who will move first, the human or computer. Assign O to the computer and X to the Human player. Ask the user to select their move using the horizontal and vertical position. For example: A1 for the upper left square, or B2 for the center square. After each move, redraw the board with the X’s and O’s in the right positions. After each game, ask the user if they want to play again. If they do, start the game again. Bullets 8 and 10 are very important. Do not’s: Don’t use User Classes or Objects Don’t use images Program must use: functions loops branching string functions
Use C++: Develop a Tic Tac Toe game that will match a player against the computer. Do’s: Use a typical 3 x 3 board. The horizontal axis should be labeled A, B, C. The vertical axis should be labeled 1, 2, 3. For Example the picture attatched. Use User-Defined Functions. Use Branching. Use Loops. Use String functions. Randomly determine who will move first, the human or computer. Assign O to the computer and X to the Human player. Ask the user to select their move using the horizontal and vertical position. For example: A1 for the upper left square, or B2 for the center square. After each move, redraw the board with the X’s and O’s in the right positions. display if there is a tie After each game, ask the user if they want to play again. If they do, start the game again. Bullets 8 and 10 are very important. Must use and do all of the bullets Do not’s: Don’t use User Classes or Objects Don’t use images Program must use: functions loops branching string functions
Complete the program 'Bcast-Reduce-Assignment.c' (Refer to 'Bcast-Reduce-Example.c') to make the program have the output as follows if we run the program using 2 processes. The input sequence is: 0 1 2 3 The output sequence is: 0 2 6 12 The code below must be used, please #include <stdio.h>#include <stdlib.h>#include <mpi.h> int main(void) { int my_rank, comm_sz; int i; int Count = 4; int Number[4]; int Result[4]; MPI_Init(NULL, NULL); MPI_Comm_size(MPI_COMM_WORLD, &comm_sz); MPI_Comm_rank(MPI_COMM_WORLD, &my_rank); if(my_rank == 0) { printf("The input sequence is: \n"); for (i = 0; i < Count; i++) { Number[i] = i; printf("%d ", Number[i]); } printf("\n"); } // Process 0 sends data to all of the processes MPI_Bcast(Number, Count, MPI_INT, 0, MPI_COMM_WORLD); for (i = 0; i < Count; i++)…
Complete the function below that takes in three integers (a,b,c) and returns the number of integers between a and b (inclusive of the endpoints) that are divisible by c. Make sure it tests a and b for divisibility by c! In [ ]: defhow_many_divisible(a,b,c):counter=0# YOUR CODE HEREraiseNotImplementedError()returncounter In [ ]: assert how_many_divisible(10,20,5) == 3 assert how_many_divisible(30,77,7) == 7 PYTHON jYPYTER
Birthday party At Lili's birthday party, there was a game arranged by Jojo as the host. That game is to distribute Y number of candy to X number of people where all the candy tastes sweet except for one last candy which tasted like rotten nuts. Candy distribution will be sequentially starting from position Z and if past the last position then the distribution of candy continues to the first position. Write down the person in which position will get the last candy. Input FormatThe first line of input is T, which is the number of test cases.The second row and the next number of T rows are X, Y, Z.X is the number of people to whom the candy will be distributed.Y is the number of candy available.Z is the starting position of the person to whom the candy will be distributed. Output FormatA string “Case #N: “ and a number representing the position of the person who got the last candy. Constraints1 ≤ T ≤ 1001 ≤ X, Y ≤ 1031 ≤ Z ≤ X Sample Input 43 4 13 5 24 2 24 5 2 Sample OutputCase #1: 1Case…
Birthday party At Lili's birthday party, there was a game arranged by Jojo as the host. That game is to distribute Y number of candy to X number of people where all the candy tastes sweet except for one last candy which tasted like rotten nuts. Candy distribution will be sequentially starting from position Z and if past the last position then the distribution of candy continues to the first position. Write down the person in which position will get the last candy. Input FormatThe first line of input is T, which is the number of test cases.The second row and the next number of T rows are X, Y, Z.X is the number of people to whom the candy will be distributed.Y is the number of candy available.Z is the starting position of the person to whom the candy will be distributed. Output FormatA string “Case #N: “ and a number representing the position of the person who got the last candy. Constraints? ≤ ? ≤ ???? ≤ ?, ? ≤ ???? ≤ ? ≤ X Sample Input 43 4 13 5 24 2 24 5 2 Sample OutputCase #1: 1Case…
CHALLENGE ACTIVITY Use C++ 1.11.2: Outputting all combinations. Output all combinations of character variables a, b, and c, in the order shown below. If a = 'x', b = 'y', and c = 'z', then the output is:xyz xzy yxz yzx zxy zyx #include <iostream>using namespace std; int main() { char a; char b; char c; cin >> a; cin >> b; cin >> c; a = 'x'; b = 'y'; c = 'z'; cout << cout << endl; return 0;}