Suppose that a student collects the following spectrophotometric data to determine the relative concentrations of HMR and MR in solution: The abosorbance at 425 nm was measured to be 0.160 and at 520 nm was 0.770, the slopes corresponding to standard Beer's Law plots were as follows: dIA = 0.072 AIB = 0.306 AIIA = 0.760 aIIB = 0.036 Using this data, calculate the ratio between the relative concentrations of MR and HMR in this solution. 0.254 Submit Answer You have entered that answer before Incorrect. Tries 16/99 Previous Tries

Suppose that a student collects the following spectrophotometric data to determine the relative concentrations of HMR and MR in solution: The abosorbance at 425 nm was measured to be 0.160 and at 520 nm was 0.770, the slopes corresponding to standard Beer's Law plots were as follows: dIA = 0.072 AIB = 0.306 AIIA = 0.760 aIIB = 0.036 Using this data, calculate the ratio between the relative concentrations of MR and HMR in this solution. 0.254 Submit Answer You have entered that answer before Incorrect. Tries 16/99 Previous Tries

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter27: Molecular Fluorescence Spectroscopy

Section: Chapter Questions

Problem 27.11QAP

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What is the concentration (M) of the following compound as measured in a 1.000 cm cuvette: Molar absorptivity constant: 3525 (M*cm)-1 and Absorption: 0.5334 Hint: Use the Beer law to solve this problem Group of answer choices 1.513E-04 1.513E+04 1.513191E-04 1.513191E+04 1.5E-04
Using the absorbance of [FeSCN]+2 at the wavelength of maximum absorption which you obtained in part B, and the diameter of the tube, obtained in part A,calculate the molar extinction coefficient. given info: Concentration of Fe3+ stock solution, C1 = 0.001 M Volume of stock Fe3+ solution pipetted, V1 = 25mL Concentration of diluted stock solution, C2 = 0.0004 M Volume of Fe2+ solution and KSCN (upon mixing) = 10mL Weight of KSCN = 1g The reaction taking place is given as: The reaction taking place is given as: F e 3+ (aq) + SC N − (aq) ⇔Fe [SCN] 2+ (aq) the concentration of [FeSCN]2+ after the mixing of Fe3+ and SCN- is 2.5 x 10-3 M. Moles of [FeSCN]2+ = 2.5 x 10-5 moles Diameter:1.2cm The wavelength at which maximum absorption takes place is = 480 nm
One common way to determine phosphorous in urine is to treat the sample after removing the protein with molybdenum (VI) and then reducing the resulting 12-molybdophosphate complex with ascorbic acid to give an intense blue-coloured species called molybdenum blue. The absorbance of molybdenum blue can be measured at 650 nm. A 24-hour urine sample was collected, and the patient produced 1122 mL in 24 hours. A 1.00 mL aliquot of the sample was treated with Mo (VI) and ascorbic acid and diluted to a volume of 50.00 mL A calibration curve was prepared by treating 1.00 mL aliquot of phosphate standard solution in the same manner as the urine sample. The absorbances of the standards and the urine sample were obtained at 650 nm and the following results were obtained. ppm, P aBSORBANCE (A) 1.003.00 0.230 2.00 0.436 3.00 0.638 4.00 0.848 Urine sample 0.518 ffind the slope and intercept, then graph it.
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Module Code & Title: CHM9011M Chromatography and Sep Sciences Section 1: Purpose Clarity of Purpose ): Clearly states the purpose of the SOP. Relevance to Task : Demonstrates the importance and relevance of the procedure. Alignment with Goals ): Shows how the procedure aligns with organisational goals.
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