Suppose that in a combined statistics class of 450 students a lecture manages to measure the weights of 75 students who registered for STA 132 and 65 students who registered for STA 122. Let X be the weight variable of Sta121 students so that the average weight is 49 and summation of square of students weights is 586884. Moreover let y be the weight varible of Sta 122 student sothat the avverage weight is 60, and the summation of the square of student weight is 595884. Assume that the sample were selected from two population that are normally distributed with unequel standard deviation. 1. Dertemine the point estimate of the difference between the two unknown population mean weights. 2 construct a 97 % confidence interval of the difference between the two unknown population weights. 3. Test at 3 % confidence level if the two unknown population mean weights are different.
Suppose that in a combined statistics class of 450 students a lecture manages to measure the weights of 75 students who registered for STA 132 and 65 students who registered for STA 122. Let X be the weight variable of Sta121 students so that the average weight is 49 and summation of square of students weights is 586884. Moreover let y be the weight varible of Sta 122 student sothat the avverage weight is 60, and the summation of the square of student weight is 595884. Assume that the sample were selected from two population that are
1. Dertemine the point estimate of the difference between the two unknown population mean weights.
2 construct a 97 % confidence interval of the difference between the two unknown population weights.
3. Test at 3 % confidence level if the two unknown population mean weights are different.
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The mathematical formulas for this solution were very unclear as the arethmetic signs on the equations were either unavailable or jinxed up.Is it possible to get a hand written solution maybe where everything is clear?
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