Suppose that x and y are of type int, z is of type double, and ch is of type char.cin >>x >> y >>ch>>If the input isz;12&45A32What will be stored in x, y, z, and ch?O a. none of theseb. x = 12 y = .45 ch ='A' and z%3D= 32.0%3|O C. X = 12 y = 45 ch ='A' and z =32.0O d. x = 12 y = 0 ch ='&' andz=45.0

The given small code belongs to C++. Correct answer is provided below with an explanation why it is…

Suppose that x and y are of type int, z is of type double, and ch is of type char. cin >>x >» y If the input is >>ch>> z; 12 &45A 32 What will be stored in x, y, z, and ch? O a. none of these O b. x = 12 y = .45 ch ='A' and z %3D = 32.0 O C.X = 12 y = 45 ch ='A' and z = 32.0 O d. x = 12 y = 0 ch ='&' and z=45.0

Suppose that x and y are of type int, z is of type double, and ch is of type char. cin >>x >» y If the input is >>ch>> z; 12 &45A 32 What will be stored in x, y, z, and ch? O a. none of these O b. x = 12 y = .45 ch ='A' and z %3D = 32.0 O C.X = 12 y = 45 ch ='A' and z = 32.0 O d. x = 12 y = 0 ch ='&' and z=45.0

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Consider the following function: double mystery(int x, double y, char ch){if (x > 0 && isupper(ch))return(sqrt(x * 1.0) + (static_cast<int>(ch) - 65));elsereturn(pow(y,3) + x + static_cast<int>(ch));}What is the output of the following C++ statements? (Assume that the output of decimal numbers is set to two decimal places.)a. cout << mystery(16, 2.0, 'A') << endl;b. cout << mystery(5, 3.0, '*') << endl;c. cout << mystery(-7, 2.5, 'T') << endl;
In each of the following code snippets, data is copied from x to y. How many bytes of data arecopied? The answer should be a C expression. (e) int x=10, y=x;(f) int x[10]; int *y = x;(g) int x[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; void f(int y[5]) { ... } int main() { f(x); }(h) int x[10], y[10]; ... memcpy(y, x, 5*sizeof(int));
In C++ 2.12 LAB: Hypotenuse Given two numbers that represent the lengths of a right triangle's legs (sides adjacent to the right angle), output the length of the third side (i.e. hypotenuse) with two digits after the decimal point. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 3.0 4.0 the output is: Hypotenuse: 5.00
Computer Science For each of the code snippet given below, identify the error and then write code after fixing the error. Given code is the simulation of grep -v command. -v prints all lines that do not match a specific pattern. void grep_inverse(char *filename, char *str) { FILE *fp; char buf[buff_size]; fp = fopen(filename, "r"); if(!fp) { perror(filename); } else { while (fgets(buf, buff_size, fp) != NULL) { if ((strstr (buf, str)) != NULL) printf("%s", buf); } } fclose(fp); }
2. Consider the following program. #include <iostream> using namespace std; void summer(int&, int); void fall(int, int&); int x; int main() { int intNum1 = 2; int intNum2 = 5; x = 6; summer(intNum1, intNum2); cout << intNum1 << " " << intNum2 << " " << x << endl; fall(intNum1, intNum2); cout << intNum1 << " " << intNum2 << " " << x << endl; return 0; } void summer(int& a, int b) { int intNum1; intNum1 = b + 12; a = 2 * b + 5; b = intNum1 + 4; } void fall(int u, int& v) { int intNum2; intNum2 = x; v = intNum2 * 4; x = u - v; } Answer the following questions: a. What is the output? Consider variable scope. b. Considering the function summer, parameter 1 is called by reference. What is passed into the function for parameter 1, i.e., what value does parameter 1 receive? c. Again, considering the function summer, parameter 2 is called by value. What occurs in memory for parameter 2 and local…
Consider the following code: tyepdef struct { char grade; float score; } student; void f() { student a = { .grade = 'C', .score = 75.0 }; student b = { .grade = 'C', .score = 75.0 }; if (!memcmp(&a, &b, sizeof(student))) { printf("Same"); } else { printf("Different"); } } What could cause the program to print "Different"? A. memcmp examines the bytes in little endian B. memcmp returns true if contents of the memory are the same; remove the ! C. memcmp always returns a non-zero value D. The compiler may have included padding in the structs E. The compiler may have arranged the fields of the two structs differently
Consider the following function: int secret(int m, int n) { int temp = n; for (int i = 1; i < abs(m); i++) temp = temp + n; if (m < 0) temp = -temp; return temp; } What is the output of the following C++ statements? i.cout << secret(5, 4) << endl; ii.cout << secret(-3, 20) << endl;
In each of the following code snippets, data is copied from x to y. How many bytes of data arecopied? The answer should be a C expression.Example: int x[10], y[10];...for (int i=0; i<10; i++)x[i] = y[i];Answer: 10*sizeof(int)Example: int *x, *y; ...; y = x;Answer: sizeof(int*) (e) int x=10, y=x;(f) int x[10]; int *y = x;(g) int x[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};void f(int y[5]) { ... }int main() { f(x); }(h) int x[10], y[10];...memcpy(y, x, 5*sizeof(int));
Write a program whose input is two integers and whose output is the two integers swapped. Ex: If the input is: 3 8 the output is: 8 3 Your program must define and call the following function. swap_values() returns the two values in swapped order.def swap_values(user_val1, user_val2) this is what I have but its not letting mt pick random numbers : def swap_values(user_val1, user_val2):#Create a temporary variable to swap the valuestemp = user_val1user_val1 = user_val2user_val2 = tempreturn user_val1,user_val2 # Take inputs from the useruser_val1 = int(input())user_val2 = int(input())x,y = swap_values(user_val1,user_val2) print(x + ' ' + y) I need the numbers to be side by side once they are answered.
Trace the following Code and then print the output. msg db 'hello world$' newline db 10,13,'$' buffer db 10 dup mov ah,9 mov dx,offset msg int 21h ;new line mov ah,9 mov dx, offset newline int 21h ;enter a string from the keyboard lea dx,buffer mov ah,0ah int 21h ;new line mov ah,9 mov dx,offset newline int 21h ;adding the $ symbol at the end of the string mov bx,0 mov bl,buffer[1] mov buffer[bx+2],'$' mov ah,9 mov dx,offset buffer+2 int 21h
Write a computer program in C that calculates the bullet train’s constant rate of acceleration, given an initial speed of 200 mi/hr. Your program reads inputs; time intervals (t) and final velocity (vf ); from an input file and output the calculated acceleration value (a) to an output file. a=(Vf-Vi)/t Hint: A bullet train slows from a speed of 200 mi/hr to 150 mi/hr in one minute. Use the equation below, where a is acceleration, t is time interval, vi is initial velocity, and vf is final velocity. Your source code should include following functions: - Main function that declares two files for input/output values, and calls the following function o A function that computes and return a, given t, vf, and vi
1. Assume x is an int which has been declared and assigned a valid value. x guaranteed to change after this code snippet. if (x<5) x--; if (x>=5) cout << x + 1; a) True b) False 2. Assume x is an int which has been declared and assigned a valid value. x guaranteed to change after this code snippet. if (x<5) x--; if (x>=5) x++; a) True b) False