Suppose we add the following instruction to MARIE's ISA: Jumpoffset X This instruction will jump to the address calculated by adding the given address, X, to the contents of the accumulator. Show how this instruction would be executed using RTN.
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A: ANSWER:-
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Q: Question// calculate physical addressing mode for the following instruction MOV AX,[BX].ALPHA if…
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Q: Suppose we add the following instruction to MARIE’s ISA: JumpOffset X This instruction will jump to…
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- A(n) ________________ instruction always alters the instruction execution sequence. A(n) ______________ instruction alters the instruction execution sequence only if a specified Condition is true.The time it takes to perform the fetch instruction and decode instruction steps is called the execution time. True or false?Suppose we add the following instruction to MARIE’s ISA: JumpOffset X This instruction will jump to the address calculated by adding the given address, X, to the contents of the accumulator. Show how this instruction would be executed using RTN.
- Suppose we add the following instruction to MARIE’s ISA: JumpIOffset X This instruction will jump to the address calculated by going to address X, then adding the value found there to the value in the AC.Show how this instruction would be executed using RTN.Suppose we add the following instruction to MARIE’s ISA:This instruction increments the value with effective address “Operand,” and if this newly incremented value is equal to 0, the program counter is incremented by 1. Basically, we are incrementing the operand, and if this new value is equal to 0, we skip the next instruction. Show how this instruction would be executed using RTN.MIPS ISA has registers of 32-bits which are employed to create a 64-bit base address which is especially used for instructions like Load Word and Store Word. May these Load Word and Store Word instruction formats contain a random pair of source registers to create the base address? If yes, explain if there will be any corresponding effects and what they will be? If no, why not?
- Q1:Suppose the initial physical address of a segment register is given by 0E41:A02EH. Determine the physical address, base and final address of that segment register of 8086 microprocessorin 80886 microprocessor Suppose that. DS = 0200H, BX = 0300H, and DI-400H Determine the memory address accessed by each of the following instructions, assuming real mode operation: (1) MOV AL,[1234H] (2) MOV AX,[BX] (3) MOV [DI]ALAssume that the MIPS instruction j Label is located at address 0x (0800 5678), and that Label is located at address 0x (0800 1234). What will the binary value of the target address field , represented in 26 bits,be?
- If the current values in the code segment register and the instruction pointer are 12AC16 and 88B616, respectively, what physical address is used in the next instruction fetch?In the MIPS micro-architecture, the PC is incremented for each instruction, during the "Instruction Fetch" stage. The value of the PC may also be updated later within the "Memory Access" phase. * If the value of the PC is: 0x0000 2F1C, what is the value of the PC after you complete the execution of the instruction: ``addi $t0, $s0, $ra``?* <!-- response -->The PC ← PC + 1 microoperation is executed at the end of every fetch cycle (to prepare for the next instruction to be fetched). However, if we execute a Jump or a JumpI instruction, the PC overwrites the value in the PC with a new one, thus voiding out the microoperation that incremented the PC. Explain how the microprogram for MARIE might be modified to be more efficient in this regard.