Susan is 2.25 m [W] of the park and her good friend, Mary, is 1.76 m [E] of the park. If it took Mary 10.0 seconds to run to Susan and back to her original position, What would be her overall velocity in m/s? 0.802 m/s [W] 4.01 m/s [W] O m/s 0.802 m/s [E]

Susan is 2.25 m [W] of the park and her good friend, Mary, is 1.76 m [E] of the park. If it took Mary 10.0 seconds to run to Susan and back to her original position, What would be her overall velocity in m/s? 0.802 m/s [W] 4.01 m/s [W] O m/s 0.802 m/s [E]

Name: Susan is 2.25 m [W] of the park and her good friend, Mary, is 1.76 m
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Description: Susan is 2.25 m [W] of the park and her good friend, Mary, is 1.76 m [E] of the park.If it took Mary 10.0 seconds to run to Susan and back to her original position, Whatwould be her overall velocity in m/s?0.802 m/s [W]4.01 m/s [W]O m/sO 0.802 m/s [

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter2: Kinematics

Section: Chapter Questions

Problem 31PE: A swan on a lake gets airborne by flapping its wings and running on top of the water. (a) If the...

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