Table 1: Estimation of Dissolved Oxygen: SI No Volume of water Initial sample (ml) burette Final burette Volume of NazS203 reading (ml) reading (ml) consumed (V2 ml) 100.0 0.0 7.4 7.4 1 100.0 7.4 14.8 7.4 2 100.0 14.8 22.1 7.3 3 Calculations: Normality of water sample: N¡V1(water sample) =N2V2(Na2S2O3) x74 N2 xV2 N1 = vi 40 1.85 x 10-3 100 N1 = 1.85 x 10-3 • Amount of Dissolved oxygen in water sample: Amount of Dissolved oxygen in water sample = N1 x equivalent weight of oxygen = 1.85 x 10-3 x 8 g/L 3D 1.85 х 10-3 х 8х 103 рpm = 14.8 PPM Amount of Dissolved oxygen in water sample = 14.8 PPM

Table 1: Estimation of Dissolved Oxygen: SI No Volume of water Initial sample (ml) burette Final burette Volume of NazS203 reading (ml) reading (ml) consumed (V2 ml) 100.0 0.0 7.4 7.4 1 100.0 7.4 14.8 7.4 2 100.0 14.8 22.1 7.3 3 Calculations: Normality of water sample: N¡V1(water sample) =N2V2(Na2S2O3) x74 N2 xV2 N1 = vi 40 1.85 x 10-3 100 N1 = 1.85 x 10-3 • Amount of Dissolved oxygen in water sample: Amount of Dissolved oxygen in water sample = N1 x equivalent weight of oxygen = 1.85 x 10-3 x 8 g/L 3D 1.85 х 10-3 х 8х 103 рpm = 14.8 PPM Amount of Dissolved oxygen in water sample = 14.8 PPM

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.16QAP

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