itanin D in 88 children who live in a northern state was measured, and the sample progortion who were not deficient was recorded. Results of a hypothesis test to decide whether over SON are vitamin D1-tample z-test for a single proportionNull value Sample proportion SE of sample proportion0.602Results880.50.0532-Test for 1 proportion (1 sided, greater than): -Vakue- 1.92a) Is the date categorical or quantitative? How do you knowCategorical since responses are in one of two possible categories.PValue- 0.0275Quantitative since the sample proportion was calculated.O Quantitative since the sampling distribution of all possibie sample proportions is approximately normal.O Categorical since t's a survey.b) State appropriate null and alternative hypotheses.Hoi B0.5.HPe0.5.c) Using the information in the output table, the test statistic iszand the -value0) If you draw a sampling distribution picture,in a standard normal distributionThe p-value is the area (probabilty)e) The definition of the p-value in context is (round percents to the nearest tenth and the proportion to 3 decimal places)percent ifpercent of the children in the state are vitamin D deficientor higher isThe chance of observing a sample proportion of

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A major credit card company is interested in the proportion of individuals who use a competitor’s credit card. Their null hypothesis is H0: p=0.65H0: p=0.65, and based on a sample they find a sample proportion of 0.70 and a pp-value of 0.053. Is there convincing statistical evidence at the 0.05 level of significance that the true proportion of individuals who use the competitor’s card is actually greater than 0.65 ?
Serum nitrite concentrations (in μmol/L) were compared between a group of unmedicated HIV+ subjects (n =7) and a control group (n = 10). The HIV+ distribution is strongly skewed.a) Use a Wilcoxon-Mann-Whitney U test to determine if there is convincing evidence at α = 0.05 thatserum nitrite levels differ between the two populations. b) What would have been the U test p-value if researchers had instead hypothesized that serum nitriteconcentrations would tend to be larger in the HIV+ population? HIV+ Control 0.266 0.167 0.269 0.201 0.299 0.205 0.335 0.232 0.503 0.234 0.846 0.260 0.946 0.268 0.288 0.301 0.305
Serum nitrite concentrations (in μmol/L) were compared between a group of unmedicated HIV+ subjects (n =7) and a control group (n = 10). The HIV+ distribution is strongly skewed. a) Use a Wilcoxon-Mann-Whitney U test to determine if there is convincing evidence at α = 0.05 thatserum nitrite levels differ between the two populations. b) What would have been the U test p-value if researchers had instead hypothesized that serum nitriteconcentrations would tend to be larger in the HIV+ population?
In a test of H0: p = 0.8 against H1: p ≠ 0.8, a sample of size 1000 produces Z = 2.05 for the value of the test statistic. Thus the p-value (or observed level of significance) of the test is approximately equal to:
A researcher reports an F-ratio with dfbetween = 2 and dfwithin = 30 for an independent-measures ANOVA. a. How many treatment conditions were compared in the experiment? b. How many subjects participated ion the experiment?
A press release states that "by an overwhelming margin, Americans want to live in a sunny place." This statement is based on data from a nationally representative sample of 2260 adult Americans. Of those surveyed, 1255 indicated that they would prefer to live in a hot climate rather than a cold climate. Suppose that you want to determine if there is convincing evidence that a majority of all adult Americans prefer a hot climate over a cold climate. (Suppose p = proportion of all adult Americans who would prefer to live in a hot climate rather than a cold climate) (a) What hypotheses should be tested to answer this question? H0: p = 0.5 versus Ha: p > 0.5 H0: p = 0.5 versus Ha: p < 0.5 H0: p ≠ 0.5 versus Ha: p = 0.5 H0: p < 0.5 versus Ha: p > 0.5 H0: p = 0.5 versus Ha: p ≠ 0.5 (b) The P-value for this test is 0.00000007. What conclusion would you reach if ? = 0.01? Fail to reject H0. We have convincing evidence that a majority of all adult Americans prefer a…
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A major credit card company is interested in the proportion of individuals who use a competitor’s credit card. Their null hypothesis is H0: p=0.65H0: p=0.65, and based on a sample they find a sample proportion of 0.70 and a pp-value of 0.053. Is there convincing statistical evidence at the 0.05 level of significance that the true proportion of individuals who use the competitor’s card is actually greater than 0.65 ? Yes, because the sample proportion 0.70 is greater than the hypothesized proportion 0.65. A Yes, because the pp-value 0.053 is greater than the significance level 0.05. B No, because the sample proportion 0.70 is greater than the hypothesized proportion 0.65. C No, since the sample proportion 0.70 is exactly 0.05 away from the hypothesized proportion 0.65. D No, because the pp-value 0.053 is greater than the significance level 0.05.
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tamin Din 88 chadren whe live in a northem state was measured, and the sampte proportion who were not defcent 1-sample test for a single preportion N Null value Sample proportion se of sample propertion Results 88 0.5 .602 Test for 1 preportion (1 sided, greater than): Vakue192