solv G and H Task (3)you are asked to perform tensile test on specimens of two different materials (A and B) and you obtained thestress-strain diagram of the two specimens as shown in Figure 2:400350300250Material A200150100500.020.040.060.080.10.120.140.160.18Strain (mm/mm)50Material B3020100.020.040.060.08О.1Strain (mm/mm)Figure 2: Tensile Test AnalysisStress(MPa)Stress (MPa) A. Which material is considered as ductile and which one is considered as brittle? Explain. What is thedifference between the two types?B. Knowing that one of these two specimens is polystyrene and the other is mild steel. Which of thesetensile tests will be for polystyrene and which one will be for the mild steel?C. What is the Ultimate Tensile Strength (UTS) for the two specimens? Which one has higher UTS?Explain your answer.D. From the tensile test for Material A. What is the value of yield strength for this material?E. From the tensile test for Material A. Calculate the Modulus of Elasticity (Young's Modulus) for thismaterial.F. Which material has higher plastic deformation before fracture?G. Suppose that the specimen of material A is unloaded before the yield strength point. For thisspecimen, sketch the elastic hysteresis loop for the elastic region of the stress-stain curve.H. Which material should you select to manufacture a mechanical part that should not change shapewith great pressure? Explain your answer.|

G. The above graph shows the elastic hysteresis loop for the elastic region of the stress-strain…

Task (3) you are asked to perform tensile test on specimens of two different materials (A and B) and you obtained the stress-strain diagram of the two specimens as shown in Figure 2: 400 350 300 250 200 Material A 150 100 50 0.02 0.04 0.06 0.0R 0.1 0.12 0.14 0.16 0.18 Strain (mm/mm) 50 Material B 30 20 10 0.02 0.04 0.06 0.08 0.1 Strain (mm/mm) Figure 2: Tensile Test Analysis Stress(MPa) Stress (MPa)

Task (3) you are asked to perform tensile test on specimens of two different materials (A and B) and you obtained the stress-strain diagram of the two specimens as shown in Figure 2: 400 350 300 250 200 Material A 150 100 50 0.02 0.04 0.06 0.0R 0.1 0.12 0.14 0.16 0.18 Strain (mm/mm) 50 Material B 30 20 10 0.02 0.04 0.06 0.08 0.1 Strain (mm/mm) Figure 2: Tensile Test Analysis Stress(MPa) Stress (MPa)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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*Only need Question 10.12 answered. Thank you! 10.11 The elasticity of a cylindrical sample of an unknown material is to be tested. The sample is 40 cm long and has a cross-sectional area of 2.5 cm2 . The sample is hung vertically and a 50 kg weight is attached to its free end. It is found that the sample stretches to a length of 40.1 cm. (a) What is the tensile stress on the sample? (b) What is the tensile strain? (c) What is Young’s modulus for this material? 10.12 (a) Bone has a tensile Young’s modulus of ?tensile = 16 × 109 N m−2 . If the sample of unknown material in Problem 10.11 was replaced with an identical sample of bone, what would the length increase of the bone be? (b) Bone has a compressive Young’s modulus of ?comp = 9 × 109 N m−2 . If the 50 kg weight was used to compress the sample rather than stretch it, how much would the length of the sample change?
The following data were obtained from a standard tensile stress test on a mild steel specimen. Graph the result and determine proportional limit stress and Young’s Modulus.
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 151 kN. - Length of the specimen is 23 mm. - The yield strength is 79 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 17 kN, iv) Young's Modulus if the elongation is 2.4 mm at 17 kN and (v) Final diameter if the percentage of reduction in area is 24 %. Find: 1)Stress at the elastic load (in N/mm2) 2)Young's Modulus of the Specimen (in N/mm2) 3)Final Area of the Specimen at Fracture (in mm) 4)Final Diameter of the Specimen after Fracture (in mm)
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 151 kN. - Length of the specimen is 23 mm. - The yield strength is 79 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 17 kN, iv) Young's Modulus if the elongation is 2.4 mm at 17 kN and (v) Final diameter if the percentage of reduction in area is 24 %. THE QUESTION IS : FIND THE Final Diameter of the Specimen after Fracture (in mm)????
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 152 kN. - Length of the specimen is 20 mm. - The yield strength is 86 kN/mm2. - The percentage of elongation is 48 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 10 kN, iv) Young's Modulus if the elongation is 2.2 mm at 10 kN and (v) Final diameter if the percentage of reduction in area is 28 %. Solution Initial Cross-sectional Area (in mm2) Answer for part 1 The Diameter of the Specimen (in mm) Answer for part 2 Final Length of the Specimen (in mm) Answer for part 3 Stress at the elastic load (in N/mm2) Answer for part 4 Young's Modulus of the Specimen (in N/mm2) Answer for part 5 Final Area of the Specimen at Fracture (in mm) Answer for part 6 Final Diameter of the Specimen after Fracture (in mm) Answer for part 7
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 157 kN. - Length of the specimen is 23 mm. - The yield strength is 89 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 18 kN, iv) Young's Modulus if the elongation is 1.3 mm at 18 kN and (v) Final diameter if the percentage of reduction in area is 25 %. Solution: Initial Cross-sectional Area (in mm2) The Diameter of the Specimen (in mm) Final Length of the Specimen (in mm) Stress at the elastic load (in N/mm2) Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 147 kN. - Length of the specimen is 28 mm. - The yield strength is 75 kN/mm2. - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 16 kN, iv) Young's Modulus if the elongation is 1 mm at 16 kN and (v) Final diameter if the percentage of reduction in area is 22 Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm) Initial Cross-sectional Area (in mm2)
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 142 kN. - Length of the specimen is 23 mm. - The yield strength is 82 kN/mm2. - The percentage of elongation is 48 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 15 kN, iv) Young's Modulus if the elongation is 1.6 mm at 15 kN and (v) Final diameter if the percentage of reduction in area is 20 %. Solution Initial Cross-sectional Area (in mm2) Answer for part 1 The Diameter of the Specimen (in mm) Answer for part 2 Final Length of the Specimen (in mm) Answer for part 3 Stress at the elastic load (in N/mm2) Answer for part 4 Young's Modulus of the Specimen (in N/mm2) Answer for part 5 Final Area of the Specimen at Fracture (in mm) Answer for part 6 Final Diameter of the Specimen after Fracture (in mm)
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 157 kN. - Length of the specimen is 23 mm. - The yield strength is 89 kN/mm2. - The percentage of elongation is 45 %. Determine the following Diameter of the specimen, Final length of the specimen, Stress under an elastic load of 18 kN, Young's Modulus if the elongation is 1.3 mm at 18 kN and Final diameter if the percentage of reduction in area is 25 %. Fine this ans 1-Initial Cross-sectional Area (in mm2) 2-The Diameter of the Specimen (in mm) 3-Final Length of the Specimen (in mm) 4-Stress at the elastic load (in N/mm2) 5-Young's Modulus of the Specimen (in N/mm2) 6-Final Area of the Specimen at Fracture (in mm) 7-Final Diameter of the Specimen after Fracture (in mm)
Given the following stress-strain graph:a. is the modulus of elasticity of "A-514" greater, less or equal to the one of "A-572"?b. from the previous question, make an estimatio for both of them, check that the graphic comes in %c. If we were to test these materials in a universal tension equipment, which one would withstand more load?d. If we were to test these materials in a universal tension machine, which one would elongate the most before fracturing? would elongate the most before fracturing? e. Of the 6 materials shown, do any behave as brittle materials? f.
Consider the tensile stress-strain diagram below. If samples 1 and 2 are identical except that they were tested at different temperatures, which sample was tested at a lower temperature? Note: This question will be marked negatively so consider your answer carefully. A. Sample 1 B. Both were tested at the same temperature/ Alby is by die dieselfde temperatuur getoets C. Sample 2
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.