650600550500450400350300250200150100500.0020.0040.0060.0080.010.0120.0140.0160.0180.02Strain mm/mmThe graph above shows the stress-strain relationship of a steel bar under tensiontest. The steel bar diameter = 8 mm and the bar gauge length = 100 mm. Determinethe following:What is the maximum yield strength that can be obtained for this sample afterperforming strain hardening if not more than 0.0025 elastic stain is allowedStress (MPa)

Answered: Image /qna-images/answer/5a3eb89c-e685-4024-b276-7b30081b7f6c.jpg

Answered: 450 400 350 300 250 200 150 100 50…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph. Answer: breaking stress,true stress at fracture and limit of proportionality.
To determine the nominal or engineering stress and strain experienced by a specimen of a material while it is subjected to a tension test, and to be able to read important values from a conventional stress-strain diagram obtained from the test. A tension test is being conducted on a steel-rod specimen with a gauge length of L0=50 mm and initial diameter of d0=13 mm. Data were collected to form the conventional stress-strain diagram as shown. From the diagram, f = 506 MPa , e = 689 MPa , g = 585 MPa , and h = 0.146 mm/mm . A) Assuming that the strain remains constant throughout the region between the gauge points, determine the nominal strain ε experienced by the rod if it is elongated to L = 53.0 mm . B) Assuming that the stress is constant over the cross-sectional area and if the tension force used is P = 16.0 kN , find the nominal stress experienced by the rod. C)Determine the force P needed to reach the ultimate stress in the steel-rod specimen.
To determine the nominal or engineering stress and strain experienced by a specimen of a material while it is subjected to a tension test, and to be able to read important values from a conventional stress-strain diagram obtained from the test.A tension test is being conducted on a steel-rod specimen with a gauge length of L0=2 in and initial diameter of d0=0.5 in. Data were collected to form the conventional stress-strain diagram as shown. From the diagram, f = 73.0 ksi , e = 101.0 ksi g=83.0ksi, and h=0.15in/in Part A - Nominal or engineering strain in the rod Assuming that the strain remains constant throughout the region between the gauge points, determine the nominal strain ε experienced by the rod if it is elongated to L = 2.5 in . Express the nominal strain in inches per inch to three significant figures. Part B - Nominal or engineering stress in the specimen Assuming that the stress is constant over the cross-sectional area and if the tension force used is P = 8.0 kips ,…
The strain rosettes shown in Figures P13.50 were used to obtain normal strain data at a point on the freesurface of a machine component.(a) determine the strain components e x, e y, and γ xy at the point.(b) determine the principal strains and the maximum in-planeshear strain at the point.
The strain rosettes shown in Figures P13.50 were used to obtain normal strain data at a point on the free surface of a machine component. In each of Problems P13.50(a) determine the strain components e x, e y, and γ xy at the point. b) determine the principal strains and the maximum in-planeshear strain at the point.
The following data were obtained from the tensile test of Aluminum alloy. The initial diameter of testspecimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine(a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and(e) Nominal Rupture Stress.
A tension test was performed on a steel specimen having an original diameter of 12.5 mm and gauge length of 50 mm. The data is listed in the table. Plot the stress–strain diagram and determine approximately the modulus of elasticity, the yield stress, the ultimate stress, and the rupture stress. Use a scale of 25 mm = 140 MPa and 25 mm = 0.05 mm/mm. Redraw the elastic region, using the same stress scale but a strain scale of 25 mm = 0.001 mm/mm.
A test piece is cut from a brass bar and subjected to a tensile test. With a load of 6.4 kN the test piece, of diameter 11.28 mm, extends by 0.04 mm over a gauge length of 50 mm. Determine: (i) the stress, (ii) the strain, (iii) the modulus of elasticity. (b) A spacer is turned from the same bar. The spacer has a diameter of 28 mm and a length of 250 mm, both measurements being made at 20~ The temperature of the spacer is then increased to 100~ the natural expansion being entirely prevented. Taking the coefficient of linear expansion to be 18 x 10-6/~ determine: (i) the stress in the spacer, (ii) the compressive load on the spacer. rC.G.] [64 MN/m 2, 0.0008, 80 GN/m 2, 115.2 MN/m 2, 71 kN.] Could you please answer thisquestion fully? If you use * could you please explain what you mean by it! Thank You :)
A mild steel bar went through a tensile test conducted at the University of San Carlos Mechanical Engineering Laboratory. The following data was obtained from the test: i. Diameter of the steel bar = 30 mm ii. Gauge length of the bar = 200 mm iii. Load at the elastic limit = 250 kN iv. Extension at a load of 150 kN = 0.21 mm v. Maximum load = 380 kN vi. Total extension = 60 mm vii. Diameter of the rod at the failure = 22.5 mm Determine the Young’s modulus, the stress at the elastic limit, the percentage elongation, and the percentage decrease in area.
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
The stress-strain diagram of a reinforcement steel having a cross-sectional diameter of 12 mmdiameter and 100 mm gage length is determined after its tensile strength test as follows. Based on the stressstrain diagram determine the followings properties of the material (Poisson’s ratio of the material is 0.32) : a) Modulus of elasticityb) Yield strengthc) Toughnessd) Resiliencee) Shear modulusf) Bulk modulusg) Ductility as described bypercent change in length
Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Determine the true stress (in MPa) at yield point. - Determine the true stress (in MPa) at point of ultimate strength. - Determine the true stress (in MPa) at fracture point. - Determine the true strain (in mm/mm) at yield point. (Use at least five decimal units) - Determine the true strain (in mm/mm) at point of ultimate strength. (Use at least five decimal units) - Determine the true strain (in mm/mm) at fracture point. (Use at least five decimal units)

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