Task 4 Here students need to calculate (a) The cutting speed (b) Turning time (c) Amount of material removed. For a specimen as shown below, if spindle rotates at N = 360 rpm, number of pass = 03, feed rate= 0.2mm/rev, if density of material=7.85× 10-6 Kg/mm³. Appendix Volume for Cylinder = rr?h Volume of frustum= nh (a?+b²+ab)/3 radii 'a' & b' height(Length) 'h'. b-a Taper angle : = tan20 h TDN Cutting speed:V : meters/min 1000 Where: V = Cutting speed in Meter/minute. T= 3.14 D = Diameter of work piece in mm N = rpm Cutting Time Length of the job to be turned NO.of cuts Time to turn mins. Feed/Rev rpm Amount of Material Removed = Original Mass – Machined Mass Original Size of Component 380 mm Machined Component 80 mm 100 mm 120 mm 6 20mm + 25mm + 40mm + 25mm 030mm

Task 4 Here students need to calculate (a) The cutting speed (b) Turning time (c) Amount of material removed. For a specimen as shown below, if spindle rotates at N = 360 rpm, number of pass = 03, feed rate= 0.2mm/rev, if density of material=7.85× 10-6 Kg/mm³. Appendix Volume for Cylinder = rr?h Volume of frustum= nh (a?+b²+ab)/3 radii 'a' & b' height(Length) 'h'. b-a Taper angle : = tan20 h TDN Cutting speed:V : meters/min 1000 Where: V = Cutting speed in Meter/minute. T= 3.14 D = Diameter of work piece in mm N = rpm Cutting Time Length of the job to be turned NO.of cuts Time to turn mins. Feed/Rev rpm Amount of Material Removed = Original Mass – Machined Mass Original Size of Component 380 mm Machined Component 80 mm 100 mm 120 mm 6 20mm + 25mm + 40mm + 25mm 030mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Note: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.
A mild steel block of width 40 mm is being milled using a straight slab cutter 70 mm diameter with 30 teeth. If the cutter rotates at 40 rpm, and depth of cut is 2 mm, what is the value of maximum uncut chip thickness when the table feed is 20 mm/min?
Suppose in a face milling operation, the dimensions of the workpiece are 5 inches by 10 inches. The cutter is 6 inches in diameter, has 8 teeth, and rotates at 300 rpm. The depth of cut is 0.125 inches and the feedrate is 0.005 inches / tooth. Assume that the specific power requirement for this material is 2 hp min / in3 and that only 75% of the cutter diameter is involved in cutting. Calculate (a) the required power, and (b) the material removal rate.
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate:
A 200 mm long magnesium alloy bar, 63 mm in diameter is turned on a lathe using a high speed steel cutter travelling at 180 mm/min. The spindle rotates at 450 rpm and lathe is equipped with a 10 kW motor, operating at a mechanical efficiency of 92%. The final diameter of the magnesium alloy bar is 59,5 mm. Indicate with a sketch the recommend size and location of the following tool angles: back rake, side rake, end relief, side relief and side and end cutting edge. Calculate the cutting time for the machining process.Calculate the required cutting force.
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A two-spindle drill cuts two holes at the same time, one 1/2 inch and one 3/4 inch. The workpiece is 1.0 inches thick. Both drills have point angles of 118 degrees and the cutting speed for the material is 300 ft/min. The rotational speed of each drill can be set individually but the feed rate for both holes must be set to the same value because they move together into the material. The feed rate is set so that the total metal removal rate of both drills combined does not exceed 1.50 in3/min. Determine (a) maximum feed rate (in/min) that can be used, (b) individual feeds (in/rev) for each hole, and (c) cutting time for the operation.
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