The 2002 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of TV watching times is normally distributed. Under 10% significance level can you conclude that the population standard deviation of TV watching times for teenagers is different from 2.23? Procedure: One variance x² Hypothesis Test Assumptions: (select everything that applies) O Population standard deviation is known O The number of positive and negative responses are both greater than 10 O Population standard deviation is unknown O Simple random sample O Normal population O Sample size is greater than 30 Step 1. Hypotheses Set-Up: is the where population mean hr Ho: G 2.23 v and the units are Ha: G 223 and the test is (Right-Tailed Step 2. The significance level a Step 3. Compute the value of the test statistic: Select an answer (Round the answer to 3 decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA PVA Provide the critical value(s) for the Rejection Region: Compute the P-value of the test statistic: left CV is and right CV is P-value is Step 5. Decision: CVA PVA Is the test statistic in the rejection region? Is the P-value less than the significance level? Conclusion: Select an answer Step 6. Interpretation: At 10% significance level we Select an answer hypothesis in favor of the alternative hypothesis. ) have sufficient evidence to reject the null
The 2002 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of TV watching times is normally distributed. Under 10% significance level can you conclude that the population standard deviation of TV watching times for teenagers is different from 2.23? Procedure: One variance x² Hypothesis Test Assumptions: (select everything that applies) O Population standard deviation is known O The number of positive and negative responses are both greater than 10 O Population standard deviation is unknown O Simple random sample O Normal population O Sample size is greater than 30 Step 1. Hypotheses Set-Up: is the where population mean hr Ho: G 2.23 v and the units are Ha: G 223 and the test is (Right-Tailed Step 2. The significance level a Step 3. Compute the value of the test statistic: Select an answer (Round the answer to 3 decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA PVA Provide the critical value(s) for the Rejection Region: Compute the P-value of the test statistic: left CV is and right CV is P-value is Step 5. Decision: CVA PVA Is the test statistic in the rejection region? Is the P-value less than the significance level? Conclusion: Select an answer Step 6. Interpretation: At 10% significance level we Select an answer hypothesis in favor of the alternative hypothesis. ) have sufficient evidence to reject the null
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Transcribed Image Text:The 2002 general Social Survey asked a large number of people how much time they spent watching TV
each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample
of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of
TV watching times is normally distributed. Under 10% significance level can you conclude that the
population standard deviation of TV watching times for teenagers is different from 2.23?
Procedure: One variance y- Hypothesis Test v
Assumptions: (select everything that applies)
O Population standard deviation is known
O The number of positive and negative responses are both greater than 10
O Population standard deviation is unknown
O Simple random sample
O Normal population
O Sample size is greater than 30
Step 1. Hypotheses Set-Up:
Họ: o
v- 2.23
where ovis the
population mean
v and the units are
hr v
H:
2.23
and the test is Right-Tailed
Step 2. The significance level a
Step 3. Compute the value of the test statistic: Select an answer v =
(Round the answer to 3
decimal places)
Step 4. Testing Procedure: (Round the answers to 3 decimal places)
CVA
PVA
Compute the P-value of the test
statistic:
Provide the critical value(s) for the Rejection Region:
left CV is
and right CV is
P-value is
Step 5. Decision:
CVA
PVA
Is the test statistic in the rejection region?
Is the P-value less than the significance level?
Conclusion: Select an answer
Step 6. Interpretation:
At 10% significance level we Select an answer v have sufficient evidence to reject the null
hypothesis in favor of the alternative hypothesis.
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