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- In a horse population, three different traits showing continuous distribution were measured,and their variances are shown in the table below:(see image) 1. Calculate the broad sense and narrow sense heritabilities for each trait.2. In the population of animals studied, which trait would respond best to selection for breeding purposes? Explain your answer.A population consists of 300 individuals with the following genotypes: AA – 100 Aa – 125 aa – 75 a. What are the values of p and q? b. Is the population in Hardy-Weinberg equilibrium? Explain.A given autosomal locus has three possible alleles (A1, A2, and A3). Assuming that the numbers of individuals with the six possible genotypes are as follows, what would be the frequency of the A1 allele in the population? A1A1 = 30 A1A2 = 27 A2A2 = 12 A1A3 = 17 A2A3 = 10 A3A3 = 4 What would be the frequency of the A1A2 genotype? Assume the population is under Hardy-Weinberg equilibrium. A. 0.03 B. 0.107 C. 0.27 D. 0.317 E. 0.09 F. 0.182
- Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…We have learned that the response to selection is equal to the selection differential times the narrow-sense heritability, and that the narrowsense heritability includes only the additive genetic variance. Why aren’t the dominance genetic variance and the gene interaction variance included? Why don’t they contribute to the genetic variation that is acted on by selection?If there is no genetic variation within a population for a given trait, what is the heritability for the trait in the population?
- How Can We Measure Allele Frequencies in Populations? The MN blood group is a single-gene, two-allele system in which each allele is codominant. Why are such codominant alleles ideal for studies of allele frequencies in a population?How Can We Measure Allele Frequencies in Populations? What are four assumptions of the HardyWeinberg law?Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?
- How Can We Measure Allele Frequencies in Populations? Drawing on your newly acquired understanding of the HardyWeinberg equilibrium law, point out why the following statement is erroneous: Because most of the people in Sweden have blond hair and blue eyes, the genes for blond hair and blue eyes must be dominant in that population.Two inbred lines of rice are intercrossed. In the F1, the variance in panicle weight is measured to be 12 g2. The F1 is selfed, and in the F2, the variance in panicle weight is 38 g2. Estimate the broad sense heritability of panicle weight in the F2 population of this experiment. If there is no genetic variation within a population for a given trait, what is the broad sense heritability value for the trait in the population?If there are 350 AA homozygotes, 75 AS heterozygotes, and 40 SS homozygotes in a population, how many A alleles are there? How many S alleles are there? What are their allele frequencies? Round to four decimal points.