The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B(group 2). A random sample of 17 rats was selected from group 1and 11 rats from group 2, Then their weight were recorded. The results are shown in the following table sd Median Mean n 3.0 1.05 3.5 17 group 1 1.15 2.0 2.20 11 group 2 F19,16,0.025 =0.386 F15,12,0.05=0.404 F16,10.0.025 =0.335 F19,16,0.05 =0.451 F15,12,01=0.496 F16,10,0.05 =0.401 F16,19,0.025 =0.371 F12,15,0.05 = 0.382 F10,16,0.025 = 0.286 F16,19,0.05 =0.437 F1215,0.1=0.475 F10,16,0.05=0.354 Construct a 95% confidence interval for the ratin of the ori
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
![The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and
B( group 2) . A random sample of 17 rats was selected from group 1and 11 rats from group 2, Then their weight were recorded.
The results are shown in the following table
sd Median Mean n
1.05
1.15
3.0
3.5 17 group 1
2.0 2.2011 group 2
F19,16,0.025 =0.386 F15,12,0.05 = 0.404 F16,10,0.025 = 0.335
F19,16,0.05 = 0.451 F15,12,0.1 =0.496| F16.10.0.05 =0.401
F16,19,0.025 =0.371 F12,15,0.05=0.382 F10,16,0.025 =0.286
F16,19,0.05 =0.437 F12,15,0.1=0.475 F10,16,0.05=0.354
Construct a 95% confidence interval for the ratio of the variances. [ Write only the final result in the box below ]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc43732a2-15cf-4d56-becd-6319fb19be9a%2F645e4d8d-1d60-4aea-aa2e-bf2e1e9ab527%2Ffbqv3v_processed.jpeg&w=3840&q=75)
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