The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2). A random sample of 16 rats was selected from group 1and 13 rats from group 2, Then their weight were recorded. The results are shown in the following table n Mean Median sd group 1 16 3.5 3.0 1.05 group 2 13 2.20 2.0 1.15 F15,12,0.05 =0.404 F19,16,0.025 = F16,10,0.025 0.335 F16,10,0.05 = 0.401 F15,12,0.1 = 0.496 F19,16,0.05 = %3D %3D F10,16,0.025 =0.286 F12,15,0.05 =0.382 F16,19,0.025 = %3D F10,16,0.05 = 0.354 F1215,0.1=0.475 F16,19,0.05 = Construct a 95% confidence interval for the ratio of the variances. [ Hint: because of the rounding select the closest interval ]

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The aim of a study is to test the ratio of
variances in the weight of two groups of rats
being under a certain drugs A ( group 1) and B
( group 2) . A random sample of 16 rats was
selected from group land 13 rats from group 2,
Then their weight were recorded. The results
are shown in the following table
n Mean Median sd
group 1 16 3.5
3.0
1.05
group 2 13 2.20 2.0
1.15
F15,12,0.05 = 0.404 F 19,16,0.025 = 0.386
F16,10,0.025 =0.335|
F16,10,0.05 =0.401 F15,12,0.1 =0.496 F19,16,0.05 =0.451
F10,16,0.025 = 0.286 F 12,15,0.05 =0.382 F16,19,0.025 = 0.371|
F10,16,0.05 = 0.354 F12,15,0.1 =0.475 F16,19,0.05 = 0.437|
Construct a 95% confidence interval for the
ratio of the variances. [ Hint: because of the
rounding select the closest interval ]
O a. None of these
O b. [ 2.488, O0.238 ]
O c. [ 2.160 , 0.309]
O d. [2.063 , 0.318]
Transcribed Image Text:The aim of a study is to test the ratio of variances in the weight of two groups of rats being under a certain drugs A ( group 1) and B ( group 2) . A random sample of 16 rats was selected from group land 13 rats from group 2, Then their weight were recorded. The results are shown in the following table n Mean Median sd group 1 16 3.5 3.0 1.05 group 2 13 2.20 2.0 1.15 F15,12,0.05 = 0.404 F 19,16,0.025 = 0.386 F16,10,0.025 =0.335| F16,10,0.05 =0.401 F15,12,0.1 =0.496 F19,16,0.05 =0.451 F10,16,0.025 = 0.286 F 12,15,0.05 =0.382 F16,19,0.025 = 0.371| F10,16,0.05 = 0.354 F12,15,0.1 =0.475 F16,19,0.05 = 0.437| Construct a 95% confidence interval for the ratio of the variances. [ Hint: because of the rounding select the closest interval ] O a. None of these O b. [ 2.488, O0.238 ] O c. [ 2.160 , 0.309] O d. [2.063 , 0.318]
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