The apparatus shown in the picture was used to measurethe cell potential during the titration of 100.0 mL of 0.125M KCI with 0.500 M AGNO3 (Ksp,ARCI = 1.8 x 10-10).Calculate the cell potential at the following points:%3!b) at Vegc) 5.00a) 5.00 mL before VegmL after VegVSCEAgHalf-cell reaction : Ag* +e →AgE° = 0.799 3 Vand potential of SCE is 0.241 V Question 41At 25°C, E° for electrode 2e + Ni2+ Ni(s) is -0.236 V,and E° for electrode Ni(OH)2 +2e Ni(s) +2 OH is-0.714, calculate the Ksp for Ni(OH)2 (s).-

Since you have asked multiple questions, we will solve the first question for you. If you want any…

The apparatus shown in the picture was used to measure the cell potential during the titration of 100.0 mL of 0.125 M KCI with 0.500 M AGNO3 (KspAgCI = 1.8 x 10-10). Calculate the cell potential at the following points: b) at Veg c) 5.00 a) 5.00 mL before Veg mL after Veg

The apparatus shown in the picture was used to measure the cell potential during the titration of 100.0 mL of 0.125 M KCI with 0.500 M AGNO3 (KspAgCI = 1.8 x 10-10). Calculate the cell potential at the following points: b) at Veg c) 5.00 a) 5.00 mL before Veg mL after Veg

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter23: Potentiometry

Section: Chapter Questions

Problem 23.23QAP: The following cell was found to have a potential of —0.492 V: Ag|AgCl(sat’d)||HA(0.200 M),NaA(0.300...

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Question

The apparatus shown in the picture was used to measure
the cell potential during the titration of 100.0 mL of 0.125
M KCI with 0.500 M AGNO3 (Ksp,ARCI = 1.8 x 10-10).
Calculate the cell potential at the following points:
%3!
b) at Veg
c) 5.00
a) 5.00 mL before Veg
mL after Veg
V
SCE
Ag
Half-cell reaction : Ag* +e →Ag
E° = 0.799 3 V
and potential of SCE is 0.241 V

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