A fluoride ion-selective electrode has a selectivity coefficient Kot F, OH- = 0.1. What will be the change in electrode potential when the pH of 1.0 × 10-4 M solution of F is raised from pH = 5.5 to pH = 11.5. The potential of an ion-selective electrode is 0.05916 E= constant + B log([A]sample + EKAI:l1) where: z = -1 for fluoride ion and assume B = 1. Express your answer in units of Volt. Do not write down the unit.

Principles of Instrumental Analysis
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ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
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Chapter23: Potentiometry
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Problem 23.7QAP
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A fluoride ion-selective electrode has a selectivity coefficient Kot
F, OH-
= 0.1. What will be the change in electrode potential when the pH of 1.0 X 10-4 M solution of F
is raised from
pH = 5.5 to pH= 11.5.
The potential of an ion-selective electrode is
0.05916
E= constant + B
log(IA]sample + E KAI'[!)
where: z = -1 for fluoride ion and assume B = 1.
Express your answer in units of Volt. Do not write down the unit.
Transcribed Image Text:A fluoride ion-selective electrode has a selectivity coefficient Kot F, OH- = 0.1. What will be the change in electrode potential when the pH of 1.0 X 10-4 M solution of F is raised from pH = 5.5 to pH= 11.5. The potential of an ion-selective electrode is 0.05916 E= constant + B log(IA]sample + E KAI'[!) where: z = -1 for fluoride ion and assume B = 1. Express your answer in units of Volt. Do not write down the unit.
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