The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: Fe(phen) 3 2+ +3 H 30* +3 H 20 → Fe(H 20) 62* + 3 phenH If the activation energy, E a is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1. what is the rate constant at 45°C? 9.6 x 10° min 1 1.1 x 10 min-1 9.3 x 10 min-1 1x10 min1 1.1 x
The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: Fe(phen) 3 2+ +3 H 30* +3 H 20 → Fe(H 20) 62* + 3 phenH If the activation energy, E a is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1. what is the rate constant at 45°C? 9.6 x 10° min 1 1.1 x 10 min-1 9.3 x 10 min-1 1x10 min1 1.1 x
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 82E: For each of the following reaction diagrams, estimate the activation energy (Ea) of the reaction:
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The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the
following chemical equation:
2+
Fe(phen) 3 2* +3 H 30 * + 3 H 20 → Fe(H 20) 6
+ 3 phenH
If the activation energy, E a, is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min
-1, what is the rate constant at 45°C?
9.6 x 10° min-1
1.1 x 10 min 1
9.3 x 10 min 1
1.1 x 10 min 1
Expert Solution
Step 1
Given :-
Activation Energy = 126KJ/mol
Rate constant at 30℃ = 9.8×10-3 min-1
To find :-
Rate constant at 45℃ = ?
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