the average width x is 31.19 cm. The deviations are: Observation Width (cm) Deviation (cm) #1 31.33 +0.14 = 31.33 - 31.19 #2 31.15 -0.04 = 31.15 - 31.19 #3 31.26 +0.07-31.26 - 31.19 #4 31.02 -0.17 = 31.02 - 31.19 #5 31.20 +0.01 31.20-31.19 What is the average deviation?

the average width x is 31.19 cm. The deviations are: Observation Width (cm) Deviation (cm) #1 31.33 +0.14 = 31.33 - 31.19 #2 31.15 -0.04 = 31.15 - 31.19 #3 31.26 +0.07-31.26 - 31.19 #4 31.02 -0.17 = 31.02 - 31.19 #5 31.20 +0.01 31.20-31.19 What is the average deviation?

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter37: Diffraction Patterns And Polarization

Section: Chapter Questions

Problem 12P: A heliumneon laser emits light that has a wavelength of 632.8 nm. The circular aperture through...

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the average width x is 31.19 cm. The deviations are:
Observation Width (cm)
Deviation (cm)
#1
31.33
+0.14 = 31.33 - 31.19
#2
31.15
-0.04 31.15 - 31.19
#3
31.26
+0.0731.26 - 31.19
#4
31.02
-0.17 31.02 - 31.19
#5
31.20
+0.01 = 31.20 - 31.19
What is the average deviation?
0.086 cm
31.5
0.25

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