The balanced equation for the decomposition of potassium chlorate is shown below. When carrled out in lab, this reaction is found to produce 340 mL of oxygen gas at STP. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 KCIO3(s) -> 2 KCI(s) + 3 02(g) 122.551 74.551 32 Determine the percent yield if the reaction consumes 2300 mg of potassium chlorate:

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Chapter5: Gases
Section: Chapter Questions
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The balanced equation for the decomposition of potassium chlorate is shown below. When carried out in lab, this reaction is found to
produce 340 mL of oxygen gas at STP. For your convenience, the molar mass of each substance is shown below their formulas (in purple).
Use this information to make the requested calculation:
2 KCIO3(s) -> 2 KCI(s) + 3 02(g)
122.551
74.551
32
Determine the percent yield if the reaction consumes 2300 mg of potassium chlorate:
Transcribed Image Text:The balanced equation for the decomposition of potassium chlorate is shown below. When carried out in lab, this reaction is found to produce 340 mL of oxygen gas at STP. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 KCIO3(s) -> 2 KCI(s) + 3 02(g) 122.551 74.551 32 Determine the percent yield if the reaction consumes 2300 mg of potassium chlorate:
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