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the balanced equation for the following situation. List the reaction type. Write Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 13.33 cg of barium chloride is reacted with 135.2 mL of a 0.250 M sulfuric acid

the balanced equation for the following situation. List the reaction type. Write Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 13.33 cg of barium chloride is reacted with 135.2 mL of a 0.250 M sulfuric acid

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter6: Chemical Reactions: An Introduction
Section: Chapter Questions
Problem 68AP
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Follow the format used in the example!!

the balanced equation for the following situation. List the reaction type. Write Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 13.33 cg of barium chloride is reacted with 135.2 mL of a 0.250 M sulfuric acid 2. N₂ (g) + 3 H₂(g) → 2 NH3(g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) 1g N₂ ? g NH3 = 61.802 cg N₂ x LR 1 mol N₂ x 2 mol NH₁ x 17.04 g NH3 = 28.02 g N₂ 1 mol N₂ 1 mol NH3 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x 1g H₂ 1 x 10² g H₂ X x 1 mol H₂ x 2.02 g H₂ 0.75168 g NH; ******* THEORETICAL YIELD 2 mol NH3 x 17.04 g NH3 = 3.3756 g NH3 3 mol H₂ 1 mol NH3 How much N₂ remains in the vessel? You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. ? g H₂ USED= 61.802 cg N2 x 1g N₂ x 1 mol N₂ x 3 mol H₂ x 2.02 g H₂ = 1 x 10² cg N₂ 28.02 g N₂ 1 mol N₂ 1 mol H₂ Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED= 0.61802 g H₂ GIVEN - 0.13366 g H₂ USED = 0.48436 g of H₂--LEFT OVER EXCESS 0.13366 g H₂
Transcribed Image Text:the balanced equation for the following situation. List the reaction type. Write Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 13.33 cg of barium chloride is reacted with 135.2 mL of a 0.250 M sulfuric acid 2. N₂ (g) + 3 H₂(g) → 2 NH3(g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) 1g N₂ ? g NH3 = 61.802 cg N₂ x LR 1 mol N₂ x 2 mol NH₁ x 17.04 g NH3 = 28.02 g N₂ 1 mol N₂ 1 mol NH3 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x 1g H₂ 1 x 10² g H₂ X x 1 mol H₂ x 2.02 g H₂ 0.75168 g NH; ******* THEORETICAL YIELD 2 mol NH3 x 17.04 g NH3 = 3.3756 g NH3 3 mol H₂ 1 mol NH3 How much N₂ remains in the vessel? You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. ? g H₂ USED= 61.802 cg N2 x 1g N₂ x 1 mol N₂ x 3 mol H₂ x 2.02 g H₂ = 1 x 10² cg N₂ 28.02 g N₂ 1 mol N₂ 1 mol H₂ Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED= 0.61802 g H₂ GIVEN - 0.13366 g H₂ USED = 0.48436 g of H₂--LEFT OVER EXCESS 0.13366 g H₂
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