   Chapter 9, Problem 10CR ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
27 views

# Consider the unbalanced equation for the combustion of propane::math> C 3 H 8 ( g ) + O 2 ( g ) → CO 2 ( g ) + H 2 O ( g ) rst, balance the equation. Then, for a given amount of propane, write the mole ratios that would enable you to calculate the number of moles of each product as well as the number of moles of O 2 that would be involved in a complete reaction. Finally, show how these mole ratios would be applied if 0.55 mole of propane is combusted.

Interpretation Introduction

Interpretation:

To balance the given reaction and show how these mole ratios will apply if 0.55 mole of propane is combusted.

Concept Introduction:

When the number of atoms of an element on the product side and on the reactant side is equal then such reaction is said to be a balanced chemical equation.

For example, the reaction between lead sulphide and oxygen is as follows:

2 PbS +  3 O22PbO +  2SO2  Reactants            Products

In combustion reaction, carbon dioxide and water are produced.

For example: the combustion reaction of ethane is following:

2 C2H6(g) + 7 O2(g)Δ4 CO2(g) + 6 H2O(g)              Reactants                         Products

The general reaction of combustion as follows:

Organic compound + O2(g) Δ CO2 (g) + H2O (l)+energy.

Explanation

In combustion reaction, organic compounds react with oxygen or air and results in the formation of water and carbon dioxide with energy. This reaction is an exothermic reaction. In this reaction, carbon is oxidized by addition of oxygen to give carbon dioxide.

For example the combustion reaction of ethane is following:

2 C2H6(g) + 7 O2(g)Δ4 CO2(g) + 6 H2O(g)              Reactants                         Products

The reaction for complete combustion of propane is as follows:

C3H8(g) + O2(g)ΔCO2(g) + H2O(g)              Reactants                         Products

To balance the reaction, multiply oxygen by 5, multiply carbon dioxide by 3 and multiply water by 4. Thus, the balance combustion reaction is given as:

C3H8(g) + 5O2(g)Δ3 CO2(g) + 4 H2O(g)              Reactants                         Products

In above reaction, one mole of propane reacts with five moles of oxygen and results in the formation of three moles of carbon dioxide and four moles of water

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