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The beam is subjected to the uniform distributed load shown. Draw the shear and moment diagrams for the beam. Take : A = C kN/m m 3 B = 2.25 m C = 3 kN/ m B В m A m 1 m Solution : |Equation of Equilibrium: C kNlm C(A+1) kN 0.5(A+1) m Ax AM Im Ay Fec A meter (a) (b)

The beam is subjected to the uniform distributed load shown. Draw the shear and moment diagrams for the beam. Take : A = C kN/m m 3 B = 2.25 m C = 3 kN/ m B В m A m 1 m Solution : |Equation of Equilibrium: C kNlm C(A+1) kN 0.5(A+1) m Ax AM Im Ay Fec A meter (a) (b)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question 3: The beam is subjected to the uniform distributed load shown. Draw the shear and moment diagrams for the beam. Take : A = C kN/m m 3 B = 2.25 m C = 3 kN/ m B В т A m Solution : Equation of Equilibrium: C kNIm C(A+1) kN 0.5(A+1) m Ax AM Im Ay Fec A meter (a) (b)
Transcribed Image Text:Question 3: The beam is subjected to the uniform distributed load shown. Draw the shear and moment diagrams for the beam. Take : A = C kN/m m 3 B = 2.25 m C = 3 kN/ m B В т A m Solution : Equation of Equilibrium: C kNIm C(A+1) kN 0.5(A+1) m Ax AM Im Ay Fec A meter (a) (b)
Ум -0; Fsc(3 /5)4 - 0.5C (4 +1)' %3Dо УF - 0; А, +Fsc (3/5)-с (4 +1)- о FBC kN BC Ar kN V, (kN)= x, (m)= M(KN.m) v3 M1 vl v,(kN)= -Lim) v,(kN): х2 x2 M,(kNm) = M,(kNm) = M3 v2 (C) (d)
Transcribed Image Text:Ум -0; Fsc(3 /5)4 - 0.5C (4 +1)' %3Dо УF - 0; А, +Fsc (3/5)-с (4 +1)- о FBC kN BC Ar kN V, (kN)= x, (m)= M(KN.m) v3 M1 vl v,(kN)= -Lim) v,(kN): х2 x2 M,(kNm) = M,(kNm) = M3 v2 (C) (d)
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