The ciphertext message produced by the RSA algorithm with key (n, k) = (2573, 1013) is 0464 1472 0636 1262 2111 Determine the original message. [Hint: The Euclidean algorithm yields 1013 · 17 = 1 (mod 2573).] Decrypt the ciphertext
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- Suppose that in a long ciphertext message the letter occurred most frequently, followed in frequency by. Using the fact that in the -letter alphabet, described in Example, "blank" occurs most frequently, followed in frequency by, read the portion of the message enciphered using an affine mapping on. Write out the affine mapping and its inverse. Example 2 Translation Cipher Associate the letters of the "alphabet" with the integers. Let and define the mapping by where is the key, the number of positions from the plaintext to the ciphertext. If our alphabet consists of through, in natural order, followed by a blank, then we have "letters" that we associate with the integers as follows:a. Excluding the identity cipher, how many different translation ciphers are there using an alphabet of n "letters"? b. Excluding the identity cipher, how many different affine ciphers are there using an alphabet of n "letters," where n is a prime?Encrypt this plaintext using Decimation Cipher with key of 3 (Use the attached photo as reference) plaintext: M A J O R
- Suppose that the most common letter and the second most common letter in a long ciphertext produced by encrypting a plaintext using an affine cipher f (p) = (ap + b) mod 26 are Z and J, respectively. What are the most likely values of a and b?Consider the affine cipher with key k = (k1, k2) whose encryption and decryption functions are given by (1.11) on page 43. Alice and Bob decide to use the prime p = 601 for their affine cipher. The value of p is public knowledge, and Eve intercepts the ciphertexts c1 = 324 and c2 = 381 and also manages to find out that the corresponding plaintexts are m1 = 387 and m2 = 491. Determine the private key and then use it to encrypt the message m3 = 173.(Hill Cipher) Decrypt the following cipher text: YZZN Using the key K =
- What is the decryption function for an affine cipher if the encryption function is c = (15p + 13) mod 26?Let's say that Alice and Bob are exchanging keys using Diffie-Hellman key exchange using multiplicative group Z*499 and generator g=7. Let's say that Alice chooses secret exponent x=23 and receives the number 234 from Bob. What number should Alice send to Bob? _____ What number do Alice and Bob compute as their shared secret? ______Suppose that when a long string of text is encrypted using a shift cipher f (p) = (p + k) mod 26, the most common letter in the ciphertext is X. What is the most likely value for k, assuming that the distribution of letters in the text is typical of English text?
- Using y=2x-1 (mod26), 1. encode GGWP 2. decode IY1- A simple encryption method is being used to encrypt a small number (called the secret number). The method by which this encryption works is as follows: I. Choose a random seed number II. Calculate the key by multiplying the seed with the secret under modulus 7 III. Finally, multiply the key with the secret to get the encrypted secret Example: If our secret number was 45Randomly choose seed = 6 key = secret x seed (mod 7) = 45 x 6 (mod 7) = 4Encrypted Secret = key x secret = 45 x 4 = 180 Based on this encryption method, when randomly picking a seed number, show which number should not be picked, so that the Encrypted Secret we end up within the end is not the same as the original Secret Number we started with.The ciphertext 75 was obtained using the RSA algorithm with n = 437 and e = 3. You know the plaintext is either 8 or 9. Determine which it is without factoring n.