The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n = 920 and the test statistic is t= 56.224. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.05. State the null and alternative hypotheses. H:H= 2.84 7:μ > 2.84 Type integers or decimals. Do not round.)

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Based on the P-value, there is or is not sufficient evidence at a significance level of 0.05 to support or warrent rejection of the claim that smokers have a mean continine level greater than the level of 2.84 ng/ mL found for nonsmokers. 

sufficient evidence at a significance level of 0.05 to
Based on the P-value, there
that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers.
the claim
Transcribed Image Text:sufficient evidence at a significance level of 0.05 to Based on the P-value, there that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. the claim
The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to
nicotine.) The sample size is n = 920 and the test statistic is t= 56.224. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a
significance level of 0.05.
State the null and alternative hypotheses.
Hot = 2.84
H,:μ > 2.84
(Type integers or decimals. Do not round.)
The test statistic is
(Round to two decimal places as needed.)
C
Transcribed Image Text:The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n = 920 and the test statistic is t= 56.224. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.05. State the null and alternative hypotheses. Hot = 2.84 H,:μ > 2.84 (Type integers or decimals. Do not round.) The test statistic is (Round to two decimal places as needed.) C
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