The coach of the Genesee Valley Swim Team claims that the probability of a chipped tooth isthe same for beginning, intermediate, and advanced swimmers. A review of last year's recordsshowed that 13 of 400 beginning swimmers chipped a tooth, 8 of 600 intermediate swimmerschipped a tooth, and 5 of 300 advanced swimmers chipped a tooth. Do these data providesufficient evidence to reject the coach's claim? Perform a chi-square test of homogeneity usinga = 0.05. In answering, be sure to address each of the five steps in a test of hypothesis.

Answered: The coach of the Genesee Valley Swim…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is lower among community college students. She selects 352 community college students at random and finds that 122 of them have a smart phone. In testing the hypotheses: Ho: p= 0.33 versus Ha: p < 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 4. Find the p-value.-- 5. The communication professor should the null hypothesis.
A 2012 article in the New England Journal reports the results of a randomized trial to assess the association between regular usage of asthma medication prior to turning 18 years old, and height at age 18 years. As per the authors, "From December 1993 through September 1995, we randomly assigned 1041 children between the ages of 5 and 13 years with mild-to-moderate asthma to one of three study groups in the double-blind, placebo-controlled CAMP trial." (reference: Kelly H, et al. Effect of Inhaled Glucocorticoids in Childhood on Adult Height. New England of Medicine (2012). 367 (10)) The random assignment groups were Budesonide, Nedocromil and placebo. The following graphic shows the distribution of female and male participant heights at different times in the study follow-up, presented for the Budesonide and placebo samples. A Unadjusted Height Distribution 200 I Budesonide I Placebo 190 180- 170- 160- 150- 140- 130- 120- 110- 100- 0- Trial entry 2 Yr Trial end Adult Trial entry 2 Yr…
an automobile engineer claims that 1in 10 automobile accidents are due to driver fatigue . if a random sample of 5 accidents observed , then the probabilty that 3 accidentsare due to drive fatigue is
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According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 320 community college students at random and finds that 135 of them have a smart phone. In testing the hypotheses: Ho: p = 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 1. This is an example of a hypothesis test. 2. Find the standard error. 3. Find the z value. 4. Find the p-value. 5. The communication professor should the null hypothesis.
A study is conducted to estimate the association between exposure to lead paint in childhood and attention-deficit hyperactivity disorder (ADHD). Data on n = 400 children are collected, and data on exposure and ADHD diagnosis are shown in Table 9–26. Estimate the crude or unadjusted relative risk. Estimate the crude or unadjusted odds ratio.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,941 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 115 of their customers and calculates that these customers used an average of 11,425 kWh of electricity last year. Assuming that the population standard deviation is 3217 kWh, is there sufficient evidence to support the power company's claim at the 0.02 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
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Recent statistics suggest that 40 percent of those who visit a retail site on the World Wide Web make a purchase. A retailer wished to verify this claim. To do so, she selected a sample of 20 “hits” to her site and found that 10 had actually made a purchase. What is the likelihood of atleast 10 purchases? What is the likelihood that 15 or more “hits” result in a purchase?
A dowser has correctly located water for a well 1 out of 2 times in Jones County. In Jones County, someone who is just guessing has a 40% chance of locating water for a well. Does this sample provide sufficient evidence that the dowser can locate water and is not just guessing?
According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 323 community college students at random and finds that 134 of them have a smart phone. In testing the hypotheses: Ho: p= 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for # 3 and #4. 1. I 4. Find the p-value.-- 5. The communication professor should the null hypothesis.
A study in a journal published by the American Academy of Pediatrics (as reported in the Miami Herald, Jan. 14, 1997) seems to suggest that preschoolers who drink more than 12 ounces of fruit juice a day tend to be heavier and shorter than preschoolers who do not. The study involved a random sample of 168 healthy youngsters of whom 59 drank on average more than 12 ounces of fruit juice per day. Each child was weighed and measured. The measurements were then converted to percentage of normal height and weight for a child of that age and gender. For example, a weight percentage of 1.1 indicates that the child is 10% heavier than average. A recorded 0.80 indicates the child is 20% below the average. An average weight is recorded as 1.0. Same with height. Column 1: Juice 1- indicates child DID drink > 12 oz 2- child DID NOT drink > 12 oz Column 2: Weight% weight converted to percent of…

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