The coats of Labrador retrievers are black, chocolate, or yellow in colour. Two genes control coat colour in these dogs. Their genotypes and phenotypes are shown below. Genotype Phenotype D_B_ Black D_bb Chocolate dd__ Yellow A black dog heterozygous for both genes, and a yellow labrador (ddBb) are crossed. Determine the phenotypic ratio of the litter produced. Enter the numbers in order of top to bottom. Black Chocolate Yellow

The coats of Labrador retrievers are black, chocolate, or yellow in colour. Two genes control coat colour in these dogs. Their genotypes and phenotypes are shown below. Genotype Phenotype D_B_ Black D_bb Chocolate dd__ Yellow A black dog heterozygous for both genes, and a yellow labrador (ddBb) are crossed. Determine the phenotypic ratio of the litter produced. Enter the numbers in order of top to bottom. Black Chocolate Yellow

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

10th Edition

ISBN:9781305967359

Author:STARR

Publisher:STARR

Chapter13: Patterns In Inherited Traits

Section: Chapter Questions

Problem 6GP: In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele...

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Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?
More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handed
The text outlines some of the problems Frederick William I encountered in his attempt to breed tall Potsdam Guards. a. Why were the results he obtained so different from those obtained by Mendel with short and tall pea plants? b. Why were most of the children shorter than their tall parents?
In guinea pigs, short hair is dominant to long hair. Also in guinea pigs, black eyes aredominant to red eyes. A male guinea pig that is heterozygous for both traits is crossedwith a female that is long haired and red eyed. What are the expected phenotypes oftheir offspring? Provide the phenotypic ratio as well.
. In the tiny model plant Arabidopsis, the recessive allele hyg confers seed resistance to the drug hygromycin, and her, a recessive allele of a different gene, confers seed resistance to herbicide. A plant that was homozygous hyg/hyg ⋅ her/her was crossed with wild type, and the F1 was selfed. Seeds resulting from the F1 self were placed on petri dishes containing hygromycin and herbicide.a. If the two genes are unlinked, what percentage of seeds are expected to grow?b. In fact, 13 percent of the seeds grew. Does this percentage support the hypothesis of no linkage? Explain. If not, calculate the number of map units between the loci.c. Under your hypothesis, if the F1 is testcrossed, what proportion of seeds will grow on the medium containing hygromycin and herbicide?
Each box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes:  What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?
In guinea pigs, black hair is dominant over white hair. If a homozygous black guinea pig (father) were crossed with a homozygous white guinea pig (mother), the first generation of offspring would be all black.Match the mother's and father's genotypes and phenotypes to their correct description. 1. mother's phenotype 2. father's phenotype 3. father's genotype 4. mother's genotype a. black b. HH c. white d. hh
Professor John decided to breed bunnies during stay-at-home because why not. She performed the following cross:Parents:brown fur, gray nose x white fur, gray noseOffspring:3/8 white fur, gray nose1/8 white fur, white nose3/8 brown fur, gray nose 1/8 brown fur, white noseBased on the phenotypes of the offspring, what are the genotypes of the parents? Make sure you define your genotypes (ie B is brown fur, b is white fur)
Red eyes is the wild-type phenotype in Drosophila, and severaldifferent genes (with each gene existing in two or more alleles) affect eye color. One allele causes purple eyes, and a different allelecauses vermilion eyes. The purple and vermilion alleles are recessive to red eye color. Two types of crosses provided thefollowing data:Cross 1: Males with vermilion eyes × females with purple eyes354 offspring, all with red eyesCross 2: Males with purple eyes × females with vermilion eyes212 male offspring with vermilion eyes221 female offspring with red eyesExplain the pattern of inheritance based on these results. Whatadditional crosses might you make to confirm your hypothesis?
Mendelian GeneticsF1 Cross: Yellow, Round x Green, RoundGgWw x ggWWCharacter: Pea color & shapeUse Punnett square and fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings.Mendelian GeneticsF1 Cross: Tall, White, Axial x Dwarf, Violet, TerminalDdwwAA x ddWWaaCharacter: Stem height, Flower color & positionUse fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings.B.A.I. For A and B,1. Identify the type ofinheritance. Justifyyour answer.2. Decode the genotypesof the individuals inthe pedigree. (Useletter A forrepresentation ofalleles.)3. List down all affected
Consider the production of flower color in the Japanese morning glory (Pharbitis nil). Dominant allelesof either of two separate genes (A_bb or aaB_) produce purple petals, A_B_ produces blue petals, andhomozygous recessives for both genes produce scarlet petals. Deduce the genotypes of parents andprogeny in the following crosses: (Tabulate your answers).PARENTS PROGENYa) blue x scarlet 1/4 blue: 1/2 purple : 1/4 scarletb) purple x scarlet 1/2 purple : 1/2 scarlet
Two guinea pigs are crossed. The father is hetereozygousblack and the mother is homozygous recessive white. What are the chances of getting a white baby guinea pig? Provide the phenotype ratio.