The combustion of propane is given by the following reaction. C3H8 + 3 O2 → 3 CO2 + 4 H2O The enthalpy of reaction is −2202.0 kJ/mol. How much energy (in joules) will be released if 55.11 grams of propane is burned. (Molar mass of propane = 44.11 g/mol).

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Q: Question attached

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