The crystalline hydrate Cd(NO3)2 .4H2O(s) loses waterwhen placed in a large, closed, dry vessel at roomtemperature:Cd(NO3)2 .4H2O(s)----->Cd(NO3)2(s) + 4 H2O(g)This process is spontaneous and ΔH° is positive at room temperature.(a) What is the sign of ΔS° at room temperature?(b) If the hydrated compound is placed in a large, closed vesselthat already contains a large amount of water vapor, doesΔS° change for this reaction at room temperature?

Chemistry for Engineering Students
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Chapter10: Entropy And The Second Law Of Thermodynamics
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Problem 10.14PAE: Enthalpy changes often help predict whether or not a process will be spontaneous. What type of...
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The crystalline hydrate Cd(NO3)2 .4H2O(s) loses water
when placed in a large, closed, dry vessel at room
temperature:
Cd(NO3)2 .4H2O(s)----->Cd(NO3)2(s) + 4 H2O(g)
This process is spontaneous and ΔH° is positive at room temperature.
(a) What is the sign of ΔS° at room temperature?
(b) If the hydrated compound is placed in a large, closed vessel
that already contains a large amount of water vapor, does
ΔS° change for this reaction at room temperature?

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