The disk has a weight of 30 lb and rolls without slipping on the horizontal surface as it oscillates about its equilibrium position. The disk is displaced by rolling it counterclockwise 0.2 rad. (Figure 1) Figure 0.5 ft k = 80 lb/ft 1 of 1 > Part A Determine the equation which describes the oscillatory motion of the disk when it is released from rest as the equation for the angular displacement of the disk in terms of time t, where t is in seconds. Assume that positive angular displacement is counterclockwise. Express the arguments of trigonometric functions in radians. Express your answer in terms of t. Express the coefficients using three significant figures. 0= 15. ΑΣΦ ↓↑ vec Submit Request Answer ? rad

The disk has a weight of 30 lb and rolls without slipping on the horizontal surface as it oscillates about its equilibrium position. The disk is displaced by rolling it counterclockwise 0.2 rad. (Figure 1) Figure 0.5 ft k = 80 lb/ft 1 of 1 > Part A Determine the equation which describes the oscillatory motion of the disk when it is released from rest as the equation for the angular displacement of the disk in terms of time t, where t is in seconds. Assume that positive angular displacement is counterclockwise. Express the arguments of trigonometric functions in radians. Express your answer in terms of t. Express the coefficients using three significant figures. 0= 15. ΑΣΦ ↓↑ vec Submit Request Answer ? rad

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The turning-moment diagram for one cycle of a multi-cylinder engine shows fluctuations in energy above and below the mean-torque line as follows: –62·5 J, +105·7 J, –27·3 J, +63·3 J, –59·1 J, +25·2 J, –99·3 J and +54 J. Sketch the diagram and use it to find the mass of the flywheel, radius of gyration 220 mm, needed to keep the engine speed within the range 898 to 902 rev/min
Determine the constant torque that must be applied to a 50-kg flywheel, with radius of gyration45 cm, to give it a frequency of 300 rpm in 10 secs if its initially at rest. Please help me solve this problem with clear and complete solution. Please also include an illustration from the given.
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. Ignore the spring's mass. (1) If the datum for gravitational potential energy is set as shown below, the the gravitational potential energy of the wheel at the state 1 is___ N m(two decimal places) (2) If the datum for gravitional potential energ is set as shown below, the gravitational potential energy of the wheel at the state 2 is___ N m (two decimal places) (3) At state 1, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (4) The…
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. Ignore the spring's mass. (5) At state 2, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (6) The elastic potential energy of the spring at the state 2 is_______(N·m) (two decimal places) (7) The instantaneous center of zero velocity (IC) of the wheel at state 1 is (8) The mass moment of inertial of the wheel about its mass center G is IG =_________(kg·m2 ) (two decimal places)
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places)
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. Ignore the spring's mass. (1) If the datum for gravitational potential energy is set as shown below, the the gravitational potential energy of the wheel at the state 1 is 0 N m(two decimal places) (2) If the datum for gravitional potential energ is set as shown below, the gravitational potential energy of the wheel at the state 2 is 0 N m (two decimal places) (3) At state 1, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (4) The…
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___ (two decimal places) (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is___ (two decimal places) (3) The stretched spring length of the spring at the state 1 is________(m) (two decimal places) (4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places) (5) The stretched spring length of the spring at the…
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. 1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___ (two decimal places) (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is___ (two decimal places) (3) The stretched spring length of the spring at the state 1 is________(m) (two decimal places) 4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places) (5) The stretched spring length of the spring at the state…
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (9) The mass moment of inertial about the IC center is IIC =_________(kg·m2 ) (two decimal places)
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. Ignore the spring's mass. (5) At state 2, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (6) The elastic potential energy of the spring at the state 2 is_______(N·m) (two decimal places) (7) The instantaneous center of zero velocity (IC) of the wheel at state 1 is (8) The mass moment of inertial of the wheel about its mass center G is IG =_________(kg·m2 ) (two decimal places) (9) The mass moment of inertial of the wheel about its…
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (7) The instantaneous center of zero velocity (IC) is A. Point A B. Point O C. Point G
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___ (two decimal places)