The empirical formula a compound of uranjum and fluorine that is composed OF - uranium and 3 2.4% Fluorine is ? 67.61- ich grand st an ele

Q: What is the empirical formula of a compound composed of 35.1 g of potassium (K) and 7.18 g of oxygen…

A: Since you have asked multiple type questions, we will solve only first  questions for you. If you…

Q: A compound contains 36.68 %C, 2.309 %H, and 61.01 %Br (by mass). Determine the empirical formula of…

A: Element C H Br Mass % 36.68 2.309 61.01 moles 36.6812 2.3091 61.0180 simple ratio of moles 4 3…

Q: Measurements show that unknown compound X has the following composition: element mass % nitrogen…

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Q: Determine the empirical formulas for compounds with the following percent compositions:(a) 15.8%…

A: Empirical formula represents the simplest whole no. ratio of the elements in the compound. It can or…

Q: An oxide of iron found in many iron ores, contains 27.9 g of iron and 8.00 g of oxygen. What is the…

A: Given data is as follows: The mass of iron = 27.9 g The mass of Oxygen = 8.00 g The empirical…

Q: Mass of Zinc and Iodine was taken during the reaction is - zinc - 2.06 g, iodine -2.15 g dry…

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Q: Nicotine is a poisonous, addictive compound found in tobacco. A sample of nicotine contains 6.16…

A: Divide each number by the smallest number 0.57 to obtain a whole number ratio We get 10C 12H 2N 1O

Q: I am so lost on how to solve this I've read the explanation but still can not get it. Looking for…

A: Express each element in grams. Consider the compound to be 100 g.  Thus, the mass of iron is 69.9 g…

Q: In 2006, a Russian team discovered an interesting molecule they called "sulflower" because of its…

A: Empirical formulas are the simplest form of notation. Convert the mass of each element to moles…

Q: 22 A compound consists of 40.00% carbon, 6.71% hydrogen and 53.29% oxygen and has a molecular mass…

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Q: what is the empirical formula of a comcompound that contains only iron and oxygen and is 22.27%…

A: Empirical formula :- The formula which gives the simplest wholenumber ratio of atoms of various…

Q: 56. I A compound is found to contain 15.94% boron and 84.06% fluorine by mass. What is the empirical…

A: Empirical formula of a compound is the simplest positive whole number ratio of atoms present in a…

Q: A compound is found to contain 40.05 % sulfur and 59.95 % oxygen by mass.What is the empirical…

A: Given:Mass percent of sulfur = 40.05 %.Mass percent of oxygen = 59.95 %.Molar mass of oxygen = 16…

Q: Hydrogen

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Q: What is the empirical formula for this compound?

A: Given :-  Percentage composition of C = 27.29 %  Percentage composition of O = 72.71 %  To determine…

Q: A compound is found to contain 63.65 % nitrogen and 36.35 % oxygen by mass. Answer: The empirical…

A: The simplest ratio of the count of different types of atoms of element which are present in a…

Q: What is the empirical formula of a compound of carbon, hydrogen, and Oxygen that contains 51.56% and…

A: Given:: %C = 51.56%  %H = 14.09 % then, empirical formula = ?

Q: The elements X and Y form a compound that is 33.33% X and 66.67% Y by mass. The atomic mass of X is…

A: Percentage of X = 33.33%  Percentage of Y = 66.67%  Atomic mass of X is twice that of Y.

Q: A compound is 22.76% Carbon, 68.30% Boron and 8.93% Hydrogen by mass. What is this compound’s…

A: The given percentage of different elements firstly changed into moles by deviding it by atomic…

Q: 9. A compound of titanium and oxygen has a composition by mass of 60 % Ti and 40 % O. Determine the…

A: In the given questions we are given that titanium is 60% and oxygen is 40%  Means for every 100 g of…

Q: Determine the Empirical Formula. (5pts each) 1. What is the empirical formula of a compound which…

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Q: Compound X is consisting of 38.70% carbon, 51.60% oxygen and the rest is hydrogen. The molar mass of…

A: Given:  Mass ℅ of carbon = 38.70 ℅ Mass ℅ of oxygen = 51.60 ℅

Q: Determine the empirical formula of a compound that is 31.63% 09 31.56 % Ti and 36.81% Fe by mass Fe…

A: Given;

Q: A compound has a molar mass of 84.0g and contains 14.3%H and 85.7%C.  Determine the empirical and…

A: Given    % H  = 14.3 %   % C   =  85.7 %   Empirical Formula   = ?  Molecular Formula  = ?

Q: 21.) In the equation: KMnO4 + KBr + H2SO4 → MnSO4 + Br2 + K2SO4 + H2O, if balanced, there would be…

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Q: Measurements show that unknown compound X has the following composition: element mass % carbon 40.9%…

A: Consider the given information is as follows; Mass percent of carbon (C) = 40.9% Mass percent of…

Q: A certain compound contains only three elements: carbon, hydrogen, and chlorine. A sample of the…

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Q: Bromoform is 94.85% bromine, 0.40% hydrogen, and 4.75% carbon by mass. Determine its empirical…

A: The given data contains,   bromine=94.85%   hydrogen=0.40%   carbon=4.75%

Q: A compound is found to contain 29.68 % sulfur and 70.32 % fluorine by mass. What is the empirical…

A: The simplest formula represents the smallest ratio of atoms present in a compound is known as…

Q: A sample compound contains 19.97g Ti and 13.37g O. Determine the empirical formula of the compound.

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Q: Ascorbic acid (vitamin C) cures scurvy is composed of 40.92 percent carbon (C), 4.58 percent…

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Q: A compound is found to contain 7.808 % carbon and 92.19 % chlorine by mass. What is the empirical…

A: Empirical formula is defined as simplest or most reduced whole number ratio of atoms present in a…

Q: A sample of a pure compound contains 68.4% chromium and 31.6% oxygen by mass. What is the empirical…

A: Let the mass of the pure compound be 100 g. Thus, mass of chromium in the compound is = 68.4 % x 100…

Q: A completely made up chemical compound (molar mass = 371.88g/mol) is made up of 40.9% F and 33.32% P…

A: Empirical formula is the formula of a compound having ratio of atoms in small possible integers.…

Q: Determine the empirical formulas for compounds with the following percent compositions: 43.6%…

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Q: A 22.15 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed…

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Q: Compound made of Answer 039 mol of iron atoms combined with 0.052 of oxygen atoms 0903 g of…

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Q: A compound is found to be 43.64% P and 56.36% O by mass. Determine its empirical formula.

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Q: a compound is 30.4% N, and 69.6% O (by mass). Calculate the empirical formula for this compound.…

A: Mass of nitrogen = 30.4 g  Mass of oxygen = 69.6 g

Q: A compound containing only sulfur and phosphorus is 50.9% S by mass; the molar mass is 252 g/mol.…

A:

Q: A 21.69 gram sample of copper is heated in the presence of excess oxygen. A metal oxide is formed…

A: * Mass of copper (Cu) = 21.69 g After heating this copper , metal oxide is formed with a mass of…

Q: If cobalt metal is mixed with excess sulfur and heated strongly, a sulfide is produced that contains…

A: The empirical formula of the sulfide has to be given.

Q: A compound contains 72% magnesium and 28% nitrogen. What is its empirical formula?

A: 1)  Compound contains 78 % Mg and 28 % N2 Atomic masses of Mg and Nitrogen = 24 and 14        Hence,…

Q: . Ascorbic acid (vitamin C) cures scurvy. It is composed of 40.92 percent carbon (C), 4.58 percent…

A:

Q: A compound is composed of 27.29% C and 72.71% O by mass. What is its empirical formula?

A: The empirical formula shows the kind and proportions of atoms in a substance in its simplest form.…

Q: One of the main chemical components of chocolate is made up of the following: 46.67% C, 4.48% H,…

A: Given data, Carbon = 46.67% = 46.67 g Hydrogen = 4.48% = 4.48 g Oxygen = 17.76% = 17.76 g Nitrogen =…

Q: C. A compound has been found to contain 38.8% K, 29.4% Mn by mass. The remainder of the compound is…

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Q: An elemental analysis of a compound containing S and O produce 50.00 % S and the rest is oxygen.…

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.