The enhanced "for..each" loop accesses specific array elements. is the original loop strucțure. replaces the older for loop. is a newer loop structure.
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- Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:Initial scores: 10, 20, 30, 40 Scores after the loop: 30, 50, 70, 40 The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. #include <iostream>using namespace std; int main() { const int SCORES_SIZE = 4; int bonusScores[SCORES_SIZE]; int i; for (i = 0; i < SCORES_SIZE; ++i) { cin >> bonusScores[i]; } /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) { cout << bonusScores[i] << " "; } cout << endl; return 0;}Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:Initial scores: 10, 20, 30, 40 Scores after the loop: 30, 50, 70, 40 The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. #include <iostream>using namespace std; int main() {const int SCORES_SIZE = 4;int bonusScores[SCORES_SIZE];int i; for (i = 0; i < SCORES_SIZE; ++i) {cin >> bonusScores[i];} /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) {cout << bonusScores[i] << " ";}cout << endl; return 0;} Please help me with this issue using c++.C++ Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:Initial scores: 10, 20, 30, 40 Scores after the loop: 30, 50, 70, 40 The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. #include <iostream>using namespace std; int main() {const int SCORES_SIZE = 4;int bonusScores[SCORES_SIZE];int i; for (i = 0; i < SCORES_SIZE; ++i) {cin >> bonusScores[i];} /* Your solution goes here */ ////for (i = 0; i < SCORES_SIZE; i++) { This is my//// current Solution////bonusScores[i] += bonusScores[i + 1]; ////////////} for (i = 0; i < SCORES_SIZE; ++i) {cout << bonusScores[i] << " ";}cout << endl; return 0;} with the for loop i have now, the…
- Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++ without using std:: Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >>…Arrays Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() {const int NUM_VALS = 4;int courseGrades[NUM_VALS];int i; for (i = 0; i < NUM_VALS; ++i) {cin >> courseGrades[i];} /* Your…Write a for loop to print all NUM_VALS elements of array hourlyTemp. Separate elements with a comma and space. Ex: If hourlyTemp = {90, 92, 94, 95}, print:90, 92, 94, 95 Your code's output should end with the last element, without a subsequent comma, space, or newline. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int hourlyTemp[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> hourlyTemp[i]; } /* Your solution goes here */ cout << endl; return 0;}
- Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…Write a for loop to initialize the following array with value 0.0. double[] balances = new double[5];Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >> courseGrades.at(i);…
- C++ 2D ARRAY, Continue this codes and change the array to seat[6][6]. Include a loop that asks the user if he wants to try again or no. If the user enters the reserved seat again then display "this seat is taken already". Upon trying again, the reserved seat displayed as (X) must be displayed. My Code: #include <iostream> using namespace std; int main() { cout << "Bus Seats:\n"; cout << "* A B C D\n" << "1 * * * *\n" << "2 * * * *\n" << "3 * * * *\n" << "4 * * * *\n"; char seat[5][5]; int row, column; char col; cout << "Enter the row of your selected seat: "; cin >> row; cout << "Enter the column of your selected seat: "; cin >> col; for(int i=0; i<5; i++){ for(int j=0; j<5; j++){ if(i==0){ switch (j) { case 0: seat[i][j]='*'; break; case 1: seat[i][j]='A'; break; case 2: seat[i][j]='B'; break; case 3: seat[i][j]='C'; break; case 4: seat[i][j]='D'; break; } } else if (j==0) { switch(i) { case 1: seat[i][j]='1';…Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes here */ return 0;}In visual basic Write a For…Next loop that will printout each value in the array from problem 4.
