Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stay the same. Be careful not to index beyond the last element. Ex: Initial scores: 10, 20, 30, 40 Scores after the loop: 30, 50, 70, 40 The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner (System.in); final int SCORES_SIZE = 4; int [] bonusScores = new int[SCORES_SIZE]; int i; for (i = 0; i < bonusScores.length; ++i) { bonusScores [i] = scnr.nextInt (); /* Your solution goes here */ for (i = 0; i < bonusScores.length; ++i) { System.out.print (bonusScores[i] + " ") ; System.out.println ();

part a- 2point) for 3 students find the average of a student by asking him how many grades do you have. The answer to this question, determine the size of the array(list of grades) and then ask the user to enter grades(the number of the grades is equal to the size of the array) then calculate the average for each student. Hence, you will calculate 3 averages. to calculate the average, use the array accumulator. Also when you get each grade validate it. validation for grade means that you check whether a grade is between 0 and 100. if the grade is negative or a grade is more than 100 then it is not valid and you have to ask the user to enter a grade again. Part b- 1 point) Find the maximum and minimum grades for each student. Part c- 1 point) Print the sorted list of the grades for each student. example: if grades user entered are: 60 78 98 23 45 then sorted list is:23 45 60 78 98 (Array not vector)

/* (name header) #include // Function declaration int main() { int al[] int a2[] = { 7, 2, 10, 9 }; int a3[] = { 2, 10, 7, 2 }; int a4[] = { 2, 10 }; int a5[] = { 10, 2 }; int a6[] = { 2, 3 }; int a7[] = { 2, 2 }; int a8[] = { 2 }; int a9[] % { 5, 1, б, 1, 9, 9 }; int al0[] = { 7, 6, 8, 5 }; int all[] = { 7, 7, 6, 8, 5, 5, 6 }; int al2[] = { 10, 0 }; { 10, 3, 5, 6 }; %3D std::cout « ((difference (al, 4) « ((difference(a2, 4) <« ((difference (a3, 4) « ((difference(a4, 2) <« ((difference (a5, 2) <« ((difference (a6, 2) <« ((difference (a7, 2) <« ((difference(a8, 1) « ((difference (a9, 6) « ((difference(a10, 4) " <« ((difference(al1, 7) « ((difference (al2, 2) == 10) ? "OK\n" : "X\n"); << "al: << "a2: %3D 7)? "OK" : "X") << std::endl == 8) ? "OK\n" : "X\n") 8) ? "OK\n" : "X\n") == 8) ? "OK\n" : "X\n") == 8) ? "OK\n" : "X\n") == 1) ? "OK\n" : "X\n") == 0) ? "OK\n" : "X\n") 0) ? "OK\n" : "X\n") == 8) ? "OK\n" : "X\n") == 3) ? "OK\n" : "X\n") == 3) ? "OK\n" : "X\n") == << "a3: == << "a4: <<…