The equilibrium constant in terms of pressures for the reduction of tungsten (IV) oxide to tungsten at 25 °C is Kp = 3.82x10-4, corresponding to the reaction ? WO₂ (s) + 2CO(g) W(s) + 2CO₂(g) If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO₂(g). Pco= PCO₂ = atm atm

The equilibrium constant in terms of pressures for the reduction of tungsten (IV) oxide to tungsten at 25 °C is Kp = 3.82x10-4, corresponding to the reaction ? WO₂ (s) + 2CO(g) W(s) + 2CO₂(g) If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO₂(g). Pco= PCO₂ = atm atm

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 87AP

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