The equilibrium constant, K, for the following reaction is 1.29x10-2 at 600 K. COCI,(g) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.194 M COCI,, 5.00x10-2 M CO and 5.00x102 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.39x10-2 mol of CO(g) is added to the flask? [COC,]=| [CO] [Cl,] MMM %3D

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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.22PAE
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The equilibrium constant, K, for the following reaction is 1.29x10-2 at 600 K.
COCI,(g) C0(g) + Cl2(g)
An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains
0.194 M COC,, 5.00x10-2 M CO and 5.00x10-2 M Cl,. What will be the
concentrations of the three gases once equilibrium has been reestablished, if
3.39x10- mol of CO(g) is added to the flask?
[COCI,] =
M
[CO]
[CL]
Transcribed Image Text:The equilibrium constant, K, for the following reaction is 1.29x10-2 at 600 K. COCI,(g) C0(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.194 M COC,, 5.00x10-2 M CO and 5.00x10-2 M Cl,. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.39x10- mol of CO(g) is added to the flask? [COCI,] = M [CO] [CL]
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