The equilibrium constant, K, for the following reaction is 1.29x102 at 600 K. COC,(g)CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.287 M COCI,, 6.09×10 M CO and 6.09x102 M Ch. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.73×102 mol of Cl,(g) is added to the flask? [COCI,] = M [CO] M (C)) M %3D

Chemistry: The Molecular Science
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Chapter12: Chemical Equilibrium
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The equilibrium constant, K, for the following reaction is 1.29x102 at 600 K.
COC,(g) C0(g) + Cl,(g)
An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.287 M COCI,, 6.09x102 M CO and 6.09x102 M Ch. What will be the
concentrations of the three gases once equilibrium has been reestablished, if 4.73×102 mol of Cl,(g) is added to the flask?
[COCL,] =
M
[CO]
(C))
M
M
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Transcribed Image Text:- TripAdvisor Facebook [Review Topics] [References] Use the References to access important values if needed for this question. The equilibrium constant, K, for the following reaction is 1.29x102 at 600 K. COC,(g) C0(g) + Cl,(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.287 M COCI,, 6.09x102 M CO and 6.09x102 M Ch. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.73×102 mol of Cl,(g) is added to the flask? [COCL,] = M [CO] (C)) M M Submit Answer Retry Entire Group 1 more group attempt remaining Previous Next Email Instructor Save and A
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