The final step of hydrogen "burning" in stars consists of combining two He nuclei to form a stable ,He nucleus plus two protons. How much energy is released in this final step? The mass energy of the ,He nucleus (without atomic electrons) is 2809.41 Mev, the mas energy of the ,He nucleus (without electrons) is 3728.40 Mev and the mass energy of a proton is 938.27 Mev. 3,He + ?,He → *,He +p + p

Principles of Physics: A Calculus-Based Text
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Chapter30: Nuclear Physics
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The final step of hydrogen "burning" in stars consists of combining two 3,He nuclei to form a stable 4,He nucleus plus two protons. How much energy is released in this final step? The mass energy of the 3,He nucleus (without atomic electrons) is 2809.41 MeV, the mass
energy of the 4,He nucleus (without electrons) is 3728.40 MeV and the mass energy of a proton is 938.27 Mev.
,Не + 3, Не — 4, Не + р + p
O 1857 MeV
O 27.8 MeV
O 1890 MeV
O 13.9 MeV
O 139 MeV
O 952.2 Mev
O No energy is released.
O 1.39 MeV
Transcribed Image Text:The final step of hydrogen "burning" in stars consists of combining two 3,He nuclei to form a stable 4,He nucleus plus two protons. How much energy is released in this final step? The mass energy of the 3,He nucleus (without atomic electrons) is 2809.41 MeV, the mass energy of the 4,He nucleus (without electrons) is 3728.40 MeV and the mass energy of a proton is 938.27 Mev. ,Не + 3, Не — 4, Не + р + p O 1857 MeV O 27.8 MeV O 1890 MeV O 13.9 MeV O 139 MeV O 952.2 Mev O No energy is released. O 1.39 MeV
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