The following data are the measures of the diameters of 36 rivet heads in millimetres 170.69 171.96 173.23 170.18 172.21 170.18 168.15 171.45 169.16 169.16 168.66 171.70 170.94 172.72 170.69 171.70 171.70 169.67 169.16 168.15 170.69 171.70 170.18 172.21 171.70 169.42 170.18 170.69 171.20 172.97 172.47 170.21 169.16 171.70 171.70 170.69 (i) Complete the table below Diameters Midpoint Frequency Cumulative Frequency 168.15 ≤ x < 168.90 168.90 ≤ x < 169.65 169.65 ≤ x < 170.40 170.40 ≤ x <171.15 171.15 ≤ x < 171.90 171.90 ≤ x < 172.65 172.65 ≤ x < 173.40 (ii) Based on the answer in (i), find the mean, median and mode. Then identify the shape of the data and state your reason. (iii) Based on the answer in (i), construct a histogram and a frequency polygon of the measurement of the diameter of rivet heads on a same graph paper and axes.
The following data are the measures of the diameters of 36 rivet heads in millimetres
|
170.69 |
171.96 |
173.23 |
170.18 |
172.21 |
170.18 |
168.15 |
171.45 |
169.16 |
|
169.16 |
168.66 |
171.70 |
170.94 |
172.72 |
170.69 |
171.70 |
171.70 |
169.67 |
|
169.16 |
168.15 |
170.69 |
171.70 |
170.18 |
172.21 |
171.70 |
169.42 |
170.18 |
|
170.69 |
171.20 |
172.97 |
172.47 |
170.21 |
169.16 |
171.70 |
171.70 |
170.69 |
(i) Complete the table below
|
Diameters |
Midpoint |
Frequency |
Cumulative Frequency |
|
168.15 ≤ x < 168.90 |
|||
|
168.90 ≤ x < 169.65 |
|||
|
169.65 ≤ x < 170.40 |
|||
|
170.40 ≤ x <171.15 |
|||
|
171.15 ≤ x < 171.90 |
|||
|
171.90 ≤ x < 172.65 |
|||
|
172.65 ≤ x < 173.40 |
(ii) Based on the answer in (i), find the mean, median and
(iii) Based on the answer in (i), construct a histogram and a frequency
(iv) Is the shape of distribution determined in (ii) can be supported by the shape of the histogram? State your reason.
Step by step
Solved in 3 steps with 1 images
