The following equation represents the oxidation of ammonia, NH3.4NH3(g) + 5O2(g)  →  4NO(g) + 6H2O(g)At the same temperature and pressure, what is the maximum volume of nitrogen monoxide that can be obtained from 7.55 × 102 L of ammonia and 7.55 × 102 L of oxygen?a. 7.55 x 102Lb. 3.36 x 102Lc. 1.7 x 103Ld. 1.51 x 103Le. 6.04 x 102L

Question
Asked Nov 4, 2019

The following equation represents the oxidation of ammonia, NH3.

4NH3(g) + 5O2(g)  →  4NO(g) + 6H2O(g)

At the same temperature and pressure, what is the maximum volume of nitrogen monoxide that can be obtained from 7.55 × 102 L of ammonia and 7.55 × 102 L of oxygen?

a. 7.55 x 102L

b. 3.36 x 102L

c. 1.7 x 103L

d. 1.51 x 103L

e. 6.04 x 102L

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Step 1
given reaction is as
The
4
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given reaction is as The 4

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Step 2
According to thveaclion, u molas N praduce
4 moles
NO
I+ ic giventnat all
same conditüons orpreseuve and lzmperatūve
kept under
help_outline

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According to thveaclion, u molas N praduce 4 moles NO I+ ic giventnat all same conditüons orpreseuve and lzmperatūve kept under

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Step 3
in terms
Thusthe mole vato can be
The volumes occupied by
each
NH3 praduces 4 L nitvic oxid
4 L
provided that enough oxygen gaic available
that ic. 5L:
help_outline

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in terms Thusthe mole vato can be The volumes occupied by each NH3 praduces 4 L nitvic oxid 4 L provided that enough oxygen gaic available that ic. 5L:

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