The following gas-phase reaction is first order: N2O5→NO2 + NO3 The activation energy of this reaction is 88 kJ/mol. The value of k at 0.0 °C is 9.16 X 103 s. (a) Calculate the value of k for this reaction at 25.0 °C (b) Assume that 2.80 mol of N2Os is in a 3.00 L container, How many moles of N2O5 would remain after 2 minutes at 25 °C?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter12: Chemical Kinetics
Section: Chapter Questions
Problem 94AE: For a first order gas phase reaction A products, k = 7.2 104s1 at 660. K and k = 1.7 102s1 at...
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The following gas-phase reaction is first order:
N2O5→NO2 + NO3
The activation energy of this reaction is 88 kJ/mol. The value of k at 0.0
°C is 9.16 X 103 s.
(a) Calculate the value of k for this reaction at 25.0 °C
(b) Assume that 2.80 mol of N2Os is in a 3.00 L container, How many
moles of N2O5 would remain after 2 minutes at 25 °C?
Transcribed Image Text:The following gas-phase reaction is first order: N2O5→NO2 + NO3 The activation energy of this reaction is 88 kJ/mol. The value of k at 0.0 °C is 9.16 X 103 s. (a) Calculate the value of k for this reaction at 25.0 °C (b) Assume that 2.80 mol of N2Os is in a 3.00 L container, How many moles of N2O5 would remain after 2 minutes at 25 °C?
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