The generic metal A forms an insoluble salt AB(s) and a complex AC5(aq).The equilibrium concentrations in a solution of AC5 were found to be [A] = 0.100 M, [C] = 0.0210 M, and [AC5] = 0.100 M.%3DDetermine the formation constant, Kf, of AC5.Kf =The solubility of AB(s) in a 1.000 M solution of C(aq) is found to be 0.153 M. What is the Ksp of AB?Ksp =

The generic metal A forms an insoluble salt AB(s) and a complex AC5(aq). The equilibrium concentrations in a solution of AC5 were found to be [A] = 0.100 M, [C] = 0.0210 M, and [AC5] = 0.100 M. Determine the formation constant, Kf, of AC5. Kf %3D The solubility of AB(s) in a 1.000 M solution of C(aq) is found to be 0.153 M. What is the Ksp of AB? Ksp =

The generic metal A forms an insoluble salt AB(s) and a complex AC5(aq). The equilibrium concentrations in a solution of AC5 were found to be [A] = 0.100 M, [C] = 0.0210 M, and [AC5] = 0.100 M. Determine the formation constant, Kf, of AC5. Kf %3D The solubility of AB(s) in a 1.000 M solution of C(aq) is found to be 0.153 M. What is the Ksp of AB? Ksp =

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 14.76QE: Calculate the solubility of copper(II) iodate, Cu(IO3)2 (Ksp = 7.4 108), in (a) water. (b) a 0.10 M...

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We began the chapter with an informal discussion of how the mineral fluorite (as shown) is formed. Fluorite, CaF2, is a slightly soluble solid that dissolves according to the equation: CaF2(s) ⇌ Ca2+(aq) + 2F−(aq)The concentration of Ca2+ in a saturated solution of CaF2 is 2.15 × 10–4 M; therefore, that of F– is 4.30 × 10–4 M, that is, twice the concentration of Ca2+. What is the solubility product of fluorite?
In photography, unexposed silver bromide was removed from film by soaking the film in a solution of sodium thiosulfate, Na2S2O3. Silver ion, Ag+, forms a soluble complex with the thiosulfate ion, S2O3-2, that has a formula of Ag(S2O3)2-3, and the formation of the complex causes the AgBr in the film to dissolve. The formation of the complex has a Kf of 2.0 x 10^13 while the Ksp of AgBr is 5.0 x 10^-13. How many grams of AgBr will dissolve in 125 mL of 1.20 M Na2S2O3 solution?
The generic metal A forms an insoluble salt AB(s) and a complex AC5(aq). The equilibrium concentrations in a solution of AC5 were found to be [A]=0.100 M, [C]=0.0340 M, and [AC5]=0.100 M. Determine the formation constant, Kf, of AC5. The solubility of AB(s) in a 1.000 M solution of C(aq) is found to be 0.1580.158 M. What is the Ksp of AB?
Consider the insoluble compound cobalt(II) carbonate , CoCO3 . The cobalt(II) ion also forms a complex with ammonia . Write a balanced net ionic equation to show why the solubility of CoCO3 (s) increases in the presence of ammonia and calculate the equilibrium constant for this reaction.For Co(NH3)62+ , Kf = 7.7×104 . Be sure to specify states such as (aq) or (s). + + K =
insoluble salt AB(s) and a complex AC5(aq). The equilibrium concentrations in a solution of AC5 were found to be [A]=0.100 M[A]=0.100 M, [C]=0.0320 M[C]=0.0320 M, and [AC5]=0.100 M[AC5]=0.100 M. Determine the formation constant, Kf, of AC5. The solubility of AB(s) in a 1.000 M solution of C(aq) is found to be 0.1520.152 M. What is the Ksp of AB?
For the chemical reaction that occurs when the precipitate forms, write a balanced, net-ionic equation for the reaction, and explain why the reaction is best represented by a net-ionic equation. Explain the purpose of drying and weighing the filter paper with the precipitate three times. In the filtrate solution, is [K+] greater than, less than, or equal to [NO3−] ? Justify your answer. Calculate the number of moles of precipitate that is produced in the experiment. Calculate the mass percent of I− in the tablet. In another trial, the student dissolves a tablet in 55.0 mL of water instead of 50.0 mL of water. Predict whether the experimentally determined mass percent of I− will be greater than, less than, or equal to the amount calculated in part (e). Justify your answer. A student in another lab also wants to determine the I− content of a KI tablet but does not have access to Pb(NO3)2 . However, the student does have access to 0.20 M AgNO3 , which reacts with I−(aq)…
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