The IR spectrum of the product of the following reaction is shown below. Propose a structure for this compound. 100 - 80- NaCN 60- OTs DMSO 40- * 20- 4500 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1)
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- Reaction of 2-methylpropanoic acid [(CH3)2CHCO2H] with SOCl2 followed by 2-methylpropan-1-ol forms X. X has a molecular ion at 144 and IR absorptions at 2965, 2940, and 1739 cm-1. Propose a structure for X.Is it possible to distinguish between the following compounds using the spectroscopic techniques covered in CHE331? If so, discuss how. If not, discuss why.Benzonitrile vs Benzaldehyde(a) UV spectroscopy(b) IR spectroscopy(c) Mass spectrometry(d) 13C NMR spectroscopy(e) 1H NMR spectroscopyWhat is the purpose for all of the following ? Carry out an electrophilic aromatic substitution reaction Prepare methyl m-nitrobenzoate by the nitration of methyl benzoate Verify the identity of a product through infrared spectroscopy
- Reaction of butanenitrile (CH3CH2CH2CN) with methylmagnesium bromide (CH3MgBr), followed by treatment with aqueous acid, forms compound G. G has a molecular ion in its mass spectrum at m/z = 86 and a base peak at m/z = 43. G exhibits a strong absorption in its IR spectrum at 1721 cm−1 and has the 1H NMR spectrum given below. What is the structure of G? We will learn about the details of this reaction in Chapter 22.Draw a structure consistent with the following set of data: a hydrocarbon with a molecular ion at m/z = 68 and IR absorptions at 3310, 3000−2850, and 2120cm−1.Reaction of pentanoyl chloride (CH3CH2CH2CH2COCl) with lithium dimethyl cuprate [LiCu(CH3)2] forms a compound J that has a molecular ion in its mass spectrum at 100, as well as fragments at m/z = 85, 57, and 43 (base). The IR spectrum of J has strong peaks at 2962 and 1718 cm-1. Propose a structure for J.
- Treatment of isobutene [(CH3)2C = CH2] with (CH3)3CLi forms a carbanion that reacts with CH2=O to form H after water is added to the reaction mixture. H has a molecular ion in its mass spectrum at m/z = 86, and shows fragments at 71 and 68. H exhibits absorptions in its IR spectrum at 3600–3200 and 1651 cm−1, and has the 1H NMR spectrum given below. Whatis the structure of H?Please provide the IR, 1H NMR and UV Spectra values of Benzoic Acid, 3-bromo-, methyl ester. And discuss how the results were obtain. For example the result for 3-(3-methoxyphenyl) propanoic acid would be written like this: 1 H NMR spectrumd (ppm in CDCI3 at 60 MHZ: 11.75 (Singlet, 1H, #7), 7.40-7.23 (Multiplet, 1H, #2), 6.85 (quartet, 3H, #1-3-6), 3.86 (Singlet, 3H, #5), 3.15-2.53 (Multiplet, 4H, #9-8). The discussion would be like this: the unknown molecule contained 12H. Revealing the presence of a peak of medium intensity at 11.75 ppm that we can associate with a carbocyclic acid. It also showed a high intensity peak at 3.86 ppm that we can associate with an ether, an alcohol or an amino group. Since the signal also shows that 3 protons are attached to it, it is therefore considered an ether (OCH3) in the unknown molecule. We also see two average peaks around 7.23 ppm and 6.85 ppm which show the presence of an aromatic.Reaction of C6H5CH2CH2OH with CH3COCl affords compound W, whichhas molecular formula C10H12O2. W shows prominent IR absorptions at3088–2897, 1740, and 1606 cm−1. W exhibits the following signals in its1H NMR spectrum: 2.02 (singlet), 2.91 (triplet), 4.25 (triplet), and 7.20–7.35(multiplet) ppm. What is the structure of W?
- An organic compound B with formula C6H14O has the following: IR Spectroscopy 2974 cm-1, 1080 cm-1 Mass Spectrometry 102 (M+), 87, 73 1H NMR Spectroscopy Eight signals at δ 1.10 (d, 3H), 1.13 (dd, 3H), 1.14 (dd, 3H), 1.59 (ddq, 1H), 1.60 (ddq, 1H), 3.19 (ddq, 1H), 3.51 (dq, 1H), 3.50 (dq, 1H). Compound B is obtained by the reaction of compound A with NaH followed by CH3CH2Br. The stereochemistry of A is "S" Using this information, deduce a plausible structure for Compound A with correct stereochemistry.Interpret the 1H NMR spectral provided for the Suzuki Cross-Coupling Reactions: Synthesis of an Unsymmetrical Biaryl via Suzuki Coupling Reaction.and label all major absorbances and what they indicate.c) FT-IR spectra of both nitro and nitrito-isomers were recorded immediately after preparation. Then small samples were exposed to heat (in oven) and their spectra were recorded again.